Answer:
The ratio 35Cl/37Cl = 3/1
Explanation:
<u>Step 1:</u> Data given
Chlorine has 2 isotopes:
- mass = 35 g/mol
- mass = 37 g/mol
Average molar mass of chlorine = 35.5 grams
<u>Step 2: </u>Calculate the % of isotopes
35x + 37y = 35.5
x+y = 1 or x = 1-y
35(1-y) + 37y = 35.5
35-35y +37y = 35.5
0.5 = 2y
y = 0.25 = 37Cl
x = 1 - 0.25 = 0.75 = 35Cl
<u>Step 3: </u>
The ratio 35Cl/37Cl = 0.75/0.25 = 3/1
Answer:
At equilibrium:
[H2] = 0.005 M
[Br2] = 0.105 M
[HBr] = 0.189 M
Explanation:
H2(g) + Br2(g) ⇄ 2HBr
an "x" value will be used from reactant to produced "2x"
so at equilibrium:
[H2] = 0.1 - x
[Br2] = 0.2 - x
[HBr] = 2x
we know that Kc=[HBr]²/[H2][Br2]
Thus 62.5 = (2x)²/(0.1-x)(0.2-x)
this generate a quadratic equation: 58.5x² - 18.75x + 1.25 = 0
the x₁ = 0.23 x₂ = 0.09457
we pick 0.09457 because the two reactants can not make more than what they have. x₁ is higher than both initial reactant concentration
Then we substitute the "x₂" value at equilibrium:
[H2] = 0.1-0.09457 = 0.005 M
[Br2] = 0.2-0.09457 = 0.105 M
[HBr] = 2*0.09457 = 0.189 M
The answer to this question I think would be 2: Better
The main difference between absolute and apparent magnitude is that apparent magnitude measures the observed brightness of an object from any point, whereas absolute magnitude calculates the brightness of the object as seen from a standard distance away from the object.
Ex: Absolute Brightness: How bright a star appears at a certain distance. Apparent Brightness: The brightness of a star as seen from Earth.
