Magnesium plays a vital role in the function and structure of the body.
The adult human body consist of 25 grams of magnesium i.e. 0.25 % of the human body composition approximately.
Therefore, for a 60 kg adult, then the amount of magnesium in their body would be
= 0.15 kg
Convert kg to g:
1 kg = 1000 g
So, 0.15 kg = 
= 150 grams
Thus, amount of magnesium in 60 kg adult is equal to 150 grams
Answer:
B or A
Explanation:
choose wether A or B... give it a higher level of thinking. and good luck!
The question is incomplete, the complete question is;
The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully equalizing the water levels inside and outside the gas-collection tube, as shown in the diagram below. The volume is measured to be 45.6mL . The atmospheric pressure in the lab is measured as 765 torr , and the equilibrium vapor pressure of water at 298 K is 24 torr .(i) The pressure inside the tube due to the H2(g)
Answer:
741 torr
Explanation:
From the question we can see that the atmospheric pressure in the lab is 765 torr.
The vapour pressure of water = 24 torr
From Dalton's law of partial pressure, we know that;
Total pressure = Pressure of the H2 + Partial pressure of water vapour
Therefore;
Pressure of H2 = Total pressure - Partial pressure of water vapour
Pressure of H2 = 765 torr - 24 torr = 741 torr
Answer:
Similarly, if magnet is held stationary and the coil is moved away and towards the magnet, the galvanometer shows deflection in similar manner. It is also seen that, the faster the change in the magnetic field, the greater will be the induced emf or voltage in the coil.
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LAw of conservation of Energy is an important concept to solve this problem. The energy released is equal to the energy absorbed.
Ice undergoes latent heat. MEaning there is a change in phase but not temperature and the energy is solved by (enthalpy of fusion)(mass) = 333.5J/g)(8.5g). =2834.75J.
This is equal to the energy released by the water. The energy is computed by (mass)(specific heat of water)(temperature change) = (255g)(4.16J/gK)(T)
Final equation is:
2834.75 = 255(4.16)(T)
T = 2.67K
