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Eddi Din [679]
3 years ago
11

DDT:

Chemistry
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

d. it does all of that and even harms humans to some extent

let me know if its right

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Help please <br> 12 point
Artyom0805 [142]
An exothermic reaction is a chemical reaction that releases energy by light or heat. It is the opposite of an endothermic reaction. im sorry i only could do one! but hope this helped!
7 0
3 years ago
ILL GIVE YOU BRAINLIEST!!!!Which of the following is an example of a description of climate? *
Murrr4er [49]

Answer:

The relative humidity in Raleigh, NC

You can search it up online. Search up what is climate change and it will give you "the weather conditions prevailing in an area in general or over a long period." (On bing)

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

6 0
3 years ago
In a combustion experiment, it was found that 12.096 g of hydrogen molecules combined with 96.000 g of oxygen molecules to form
Mkey [24]
The mass change, or the mass defect, can be calculated by the formula that is very known to be associated with Albert Einstein. 

E = Δmc²
where
E is the energy gained or released during the reaction
c is the speed of light equal to 3×10⁸ m/s
Δm is the mass change

(1.715×10³ kJ)(1,000 J/1 kJ) = Δm(3×10⁸ m/s)²
Δm = 1.91×10⁻¹¹ kg
5 0
3 years ago
Chlorine melts at 172k what is chlorine’s melting point in c
e-lub [12.9K]

You can use the formula: C = k - 273 to solve this problem. C stands for Celsius, and k stands for kelvin. Given the information that the Kelvin is 172k, then you can plug it into the equation and get C = (172) - 273. The correct melting point in C is -101°C. Hope this helped!


5 0
3 years ago
For the reaction N2 + 3H2 - 2NH3, how many moles of nitrogen are required to produce 9.58 mol of ammonia?
V125BC [204]

Answer:

3.193 mol

Explanation:

The reaction is

N_2+3H_2\rightarrow 2NH_3

We use the stoichiometry in order to find the moles of nitrogen required.

9.58\ \text{mol of }NH_3\times \dfrac{1\ \text{mol of }N_2}{2\ \text{mol of }NH_3}

=3.193\ \text{mol of }N_1

The amount of nitrogen required is 3.193 mol to produce 9.58 mol of ammonia.

5 0
3 years ago
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