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Ainat [17]
3 years ago
6

design the psuedocode for a program that allows a user to enter 10 numbers, then displays them in the reverse order of their ent

ry?
Computers and Technology
1 answer:
enyata [817]3 years ago
8 0
This is how I would go about it:
1. Ask user to key in numbers. I could take each number in a single line.
2. save each input in a vector.
3. print out the vector starting at location (vector.size()-1) to location 0
You might be interested in
I have this assignment due TONIGHT BEFORE 10PM! Please help. 50 points for whoever will help!! Here is the assignment.
saveliy_v [14]

Answer:

# include <iostream.h>

# include <conio.h>

using namespace std;

int generatelist ( int z[]);

int addlist(int x []; int y []);

int mullist(int x []; int y []);

int displayList(int z[]);

main()

{

int a[10] , b[10], add[10], mul[10];

cout<<"Enter value in array a";

generatelist(a[10]);

cout<<"Enter value in array b";

generatelist(b[10]);

for (int i=0; i<=9; i++)

{

add[i]=addlist( a[i], b[i]);

cout<<"sum of list = "<< add[i];

}

for (int i=0; i<=9; i++)

{

mul[i]=mullist( a[i], b[i]);

cout<<"multiplication of list = "<< mul[i];

}

for (int i=0; i<=9; i++)

{

displayList(a[i]);

}

for (int i=0; i<=9; i++)

{

displayList(b[i]);

}

for (int i=0; i<=9; i++)

{

displayList(add[i]);

}

for (int i=0; i<=9; i++)

{

displayList(mul[i]);

}

getch();

}

int generatelist ( int z[])

{

for (int j=0 ; j<=9 ; j++)

{

cin>>z[j];

return z[j]

}

}

int addlist(int x []; int y [])

{

int add

add=x+y;

return add;

}

int mullist(int x []; int y [])

{

int mul

mul=x*y;

return mul;

}

int displayList(int z[]);

{

for(int i=0; i<=9;i++)

cout << z[i]

}

7 0
4 years ago
In which type of situation would it make sense to use edge computing?
ZanzabumX [31]

A type of situation in which it would make sense to use edge computing is: b. where critical decisions must be made on a split-second basis.

<h3>What is edge computing?</h3>

Edge computing can be defined as a distributed computing system that involves the deployment of computing and storage resources closer to the sources of data, so as to save time and enhance the decision-making process.

This ultimately implies that, a type of situation in which it would make sense to use edge computing is a scenario where critical decisions must be made on a split-second basis.

Read more on edge computing here: brainly.com/question/23858023

#SPJ1

<u>Complete Question:</u>

In which type of situation would it make sense to use edge computing?

a. where data is uploaded to a server at a scheduled time each week

b. where critical decisions must be made on a split-second basis

c. where users are in close proximity to the central data server

d. where there are few or no digital devices to capture

e. i don't know this yet

4 0
2 years ago
A startup disk cannot be detected when booting a computer. The disk's pressence is reported by the system firmware, But Windows
olasank [31]

Answer:

Bootrec.exe

Explanation:

The process of turning on a computer system is called booting. When a computer system boots, it runs the post test and loads into memory, the information or program needed to run the operating system, and then locates the operating system from the boot manager record in the disk partitions. When the disk is failed to be recorded, or the boot manager or sector is corrupt or lost, the bootrec.exe command is used in the command prompt to correct these problems.

8 0
3 years ago
A large gambling company needs to be able to accept high volumes of customer wagers within short timeframes for high-profile spo
Dima020 [189]

Answer: A. a mobile app that only accepts wagers based on the user's location

Explanation:

Elastic cloud simply refers to the cloud computing offering which due to the need for change helps in the provision of variable service levels.

Based on the information given in the question, an effective elastic Cloud solution that can meet this client’s needs is a mobile app that only accepts wagers based on the user's location.

Since there are strict laws that prohibit gambling activities outside the licensed zones, the user location is vital in the mobile app.

5 0
3 years ago
Consider designing a program where you need to store information about every student ASU. You need to be able to quickly determi
gulaghasi [49]

Answer:

Check the explanation

Explanation:

Both Arrays and Linked List can be used to store linear data of similar types, but they both have some advantages and disadvantages over each other. To store information about every student we can use an array

Reason:

In the array the elements belong to indexes, i.e., if you want to get into the fourth element you have to write the variable name with its index or location within the square bracket.

In a linked list though, you have to start from the head and work your way through until you get to the fourth element.

Accessing an element in an array is fast, while Linked list takes linear time, so it is quite a bit slower.

Example: store the data of students and have faster access and this program in example also do sorting

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

// struct person with 3 fields

struct Student {

   char* name;

   int id;

   char age;

};

// setting up rules for comparison

// to sort the students based on names

int comparator(const void* p, const void* q)

{

   return strcmp(((struct Student*)p)->name,

                 ((struct Student*)q)->name);

}

// Driver program

int main()

{

   int i = 0, n = 5;

   struct Student arr[n];

   // Get the students data

   arr[0].id = 1;

   arr[0].name = "bd";

   arr[0].age = 12;

   arr[1].id = 2;

   arr[1].name = "ba";

   arr[1].age = 10;

   arr[2].id = 3;

   arr[2].name = "bc";

   arr[2].age = 8;

   arr[3].id = 4;

   arr[3].name = "aaz";

   arr[3].age = 9;

   arr[4].id = 5;

   arr[4].name = "az";

   arr[4].age = 10;

   // Print the Unsorted Structure

   printf("Unsorted Student Records:\n");

   for (i = 0; i < n; i++) {

       printf("Id = %d, Name = %s, Age = %d \n",

              arr[i].id, arr[i].name, arr[i].age);

   }

   // Sort the structure

   // based on the specified comparator

   qsort(arr, n, sizeof(struct Student), comparator);

   // Print the Sorted Structure

   printf("\n\nStudent Records sorted by Name:\n");

   for (i = 0; i < n; i++) {

       printf("Id = %d, Name = %s, Age = %d \n",

              arr[i].id, arr[i].name, arr[i].age);

   }

   return 0;

}

Output:

Unsorted Student Records: Id = 1, Name = bd, Age = 12 Id = 2, Name = ba, Age = 10 Id = 3, Name = bc, Age = 8 Id = 4, Name = aaz, Age = 9 Id = 5, Name = az, Age = 10

6 0
4 years ago
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