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Aleksandr-060686 [28]
3 years ago
7

What is the purpose of the scientific method?

Chemistry
2 answers:
frozen [14]3 years ago
5 0

Answer:

B. To make a guess in order to prove a hypothesis.

Explanation:

Misha Larkins [42]3 years ago
5 0
D. To provide a reliable answer to a specific question
You might be interested in
H
Irina18 [472]

Answer:

Hehehe :)

Interesting.

Phase 1.

Zinc heated in Air

2Zn + O₂ = 2ZnO

Zinc Oxide is formed.

SOLID A = (ZnO)ZINC OXIDE

Phase 2.

Zinc Oxide is heated with Powdered Magnesium.

magnesium would displace Zinc since its higher in the series.

ZnO + Mg = MgO + Zn

SOLID B + SOLID C = MgO(Magnesium Oxide) + Zn(Zinc metal)

At Phase 3...( 1st Aspect)

Both MgO and Zn can react with Dilute HCl.

Now the products required from the question are a "SOLUTION D" AND "GAS E".

When MgO reacts with Dilute HCl

The products are

MgO + 2HCl = MgCl₂ + H₂O

Now H₂O could be steam(gas) or Water :(

This is a little Uncertain.

But if we use Zn as the one reacting with Dilute HCl

We have

Zn + 2HCl = ZnCl₂ + H₂

Now I'll go with this cos H₂ is simply Hydrogen Gas.

SOLUTION D + GAS E = ZnCl₂(Zinc Chloride) + H₂(Hydrogen Gas)

2nd aspect of Phase 3 ( or denominator)

ELECTROLYSIS OF MOLTEN B

B = MgO

MOLTEN B = MOLTEN MAGNESIUM CHLORIDE.

From Electrolysis of MgO

Mg²⁺ + 2e- = Mg

2O²⁻ = O₂ + 2e⁻

Combining Both Equations.

Mg²⁺ + 2O²⁻ = 2Mg(ₛ) + O₂(g)

Magnesium is a Silvery Metal :)

and Oxygen is a Gas.

Wow!!!

So this automatically makes "SILVERY METAL F" AND "GAS G" TO BE MAGNESIUM AND OXYGEN RESPECTIVELY.

SILVERY METAL F = MAGNESIUM

SILVERY METAL F = MAGNESIUMGAS G = OXYGEN

All the way down to phase 5 now.

Hope you're with me?

Now CuSO₄ is added to Mixture of Mg and O₂. Oxygen would prolly escape into the atmosphere

Leaving Mg to react with CuSO₄

Mg + CuSO₄ = MgSO₄(aq) + Cu(s)

Copper when precipitated from solution sometimes has Brown Pink Color.

MgSO₄ is Solid.

Niceeeee

That's exactly what they need as the answer.

Automatically...

BROWN PINK SOLID H = COPPER(CU)

SOLUTION I = MgSO₄(MAGNESIUM SULPHATE)

Hope this Helps :)

Have a great day.

3 0
3 years ago
Question 3
hammer [34]

Answer:

in the excited state

Explanation:

Because in excited state an atom has more energy

5 0
3 years ago
Read 2 more answers
Consider the hydrate FeSO4 • 7H2O.
DochEvi [55]
The molar mass of the hydrate is 278.06
The molar mass of the anhydrous salt is 151.92
The molar mass of water in the hydrate is 126.14
7 0
3 years ago
Read 2 more answers
The following data was collected when a reaction was performed experimentally in the laboratory. Determine the ammount of NaNO3
zepelin [54]

equalize the coefficients:

Al(NO3)3+3NaCl=3NaNO3+AlCl3

according to the equation 1 mol Al(NO3)3 reacted with 3 moles NaCl. hence, 4 moles Al(NO3)3 should react with 12 moles NaCl, and 9 moles reacted NaCl. So NaCl is limiting, we decide further on this reagent.

\frac{9}{3}=\frac{x}{3}

3

9

=

3

x

x=9

9 moles NaNO3

6 0
3 years ago
What is the boiling point elevation constant, Kb, of diethyl ether if 38.2 g of the nonelectrolyte benzophenone, C6H5COC6H5, dis
kakasveta [241]

Answer: the boiling point elevation constant is 1.73^0C/m

Explanation:

Elevation in boiling point is given by:

\Delta T_b=i\times K_b\times m

\Delta T_b=T_b-T_b^0= = Elevation in boling point

i= vant hoff factor = 1 (for non electrolyte)

K_b =boiling point constant = ?

m= molality

\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (diethylether)= 330 g = 0.33 kg

Molar mass of solute (benzophenone)= 182 g/mol

Mass of solute (benzophenone) = 38.2 g

(35.7-34.6)^0C=1\times K_b\times \frac{38.2g}{182g/mol\times 0.33kg}

K_b=1.73^0C/m

Thus the boiling point elevation constant is 1.73^0C/m

3 0
3 years ago
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