The first thing you need to do is calculate the slope. pick 2 of the ordered pairs.
i'll use (1, 4) and (0, 6)
m = (6 - 4)/(0 - 1)
m = (2)/(-1)
m = -2
so the slope is -2. slope intercept form is written as y = mx + b and you have one part of that equation
y = -2x + b
to find b, use one of the selected points. i'll use (0, 6).
(6) = -2(0) + b
6 = b
b = 6
therefore:
y = -2x + 6
3,500 kilometers in one day
Answer:
(a^3-b^3)
Step-by-step explanation:
According to the formula
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
That is,
Consider X be the length of the pregnancy
Mean and standard deviation of the length of the pregnancy.
Mean 
Standard deviation \sigma =15
For part (a) , to find the probability of a pregnancy lasting 308 days or longer:
That is, to find 
Using normal distribution,



Thus 
So 




Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.
This the answer for part(a): 0.00256
For part(b), to find the length that separates premature babies from those who are not premature.
Given that the length of pregnancy is in the lowest 3%.
The z-value for the lowest of 3% is -1.8808
Then 
This implies 
Thus the babies who are born on or before 238 days are considered to be premature.