Answer: In order for you to realize there has been a sensory change, it has to reach the <u>perceptual</u> level of processing.
Mailto, followed by the email address.
E.g.: <span><a href="mailto:
[email protected]">Mail me!</a></span>
Answer:
i could be completely wrong, but my guess is "while"
Explanation:
The answer is: [B]: " 2 " .
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Explanation:
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Given the chemical equation:
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<u> ? </u> H₂ + O₂ → 2 H₂<span>O ;
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</span> → <span> We are asked, "What coefficient, if any — should be put in front of the: " H</span>₂ " ;
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(which is on the "left-hand side" side of the chemical equation given— the "reactants") ;
→ to get a balanced chemical equation?
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→ Let us examine the "right-hand side" of this chemical equation—the product(s). In this case, the "product" given is: " 2 H₂O " .
So, on the "right hand side", we have:
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1) 4 "H's" → {Two "H₂" 's = 2 * 2 = "4 H's"} ; <u><em>and</em></u>:
2) 2 "O's" → { Two "O's").
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So, the left-hand side should have:
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1) 4 "H's" ; <u><em>and</em></u>:
2) 2 "O's" ;
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Let us examine the left-hand side (the "reactants").
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" <u> ? </u><u /> H₂ + O₂ " ;
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On the left-hand side, we already have:
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1) " 2 O's " ; → one "O₂" = "2 O's" ; and:
2) "2 H's " ; → one "H<span>₂" .</span>
Now, we would need:
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A "<u>total of "4 H's</u>". Is there any number we could put as a coefficient on the other reactant, which happens to be: "H₂" ; to make a <u><em>total of</em></u> "4 H's" ?
{Note: There are only these TWO (2) reactants in this chemical equation.}.
→ The "H₂" ; as it stands alone, is insufficient—since that would be only "2 H's".
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→ Thus, we can rule out: "Answer choices: [A] and [D]."
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<u>Note</u>:
→ Choice [A]: "1" ; The coefficient, "1"; is generally not (never?) used; and basically would function as the same as:
→ Choice: [D]: "<span>no coefficient is needed".
</span>→ <span>Choices [A] & [D]: would leave us with only "2 H's" on the "reactants side" (i.e. "left-hand side of the equation"; and we need FOUR ("4 H's").
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Since we are given: "H</span>₂" ; what coefficient could we put in front of this to get: "4 H's" ? (4÷2 =2). So we could put a "2" in front of the "H₂" ; to get:
"4 H's". The coefficient, "2" , corresponds directly with:
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→ Answer choice: [B]: "2" .
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{ <u>NOTE</u>: The remaining answer choice, [C], which is, "3" ; is INCORRECT; since 3 "H₂'s" would be "6 H's" ; (since 3 * "2 H's" equal "6 H's") ; which is too many "H's" → We need <u>exactly</u> "4 H's".}.
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So, the correctly balanced equation is:
2 H₂ + O₂ → 2 H₂O ;
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→ The coefficient that goes before the "H₂" ; to make this chemical equation balanced, is: "2" .
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The correct answer is: [B]: "2" .
→ The coefficient that goes before the "H₂" is: "2" .
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Hope this answer—and {lengthy} explanation—is of help!
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