Now i got the answer you do:
2/5 x4=8/5
8/5 + 2/5=10/5
which is 10 candies
<h3>
Answer: ds/dt = 11</h3>
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Work Shown:
Before we can use derivatives, we need to find the value of s when (x,y) = (15,20)
s^2 = x^2+y^2
s^2 = 15^2+20^2
s^2 = 225+400
s^2 = 625
s = sqrt(625)
s = 25
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Now we can apply the derivative to both sides to get the following. Don't forget to use the chain rule.
s^2 = x^2 + y^2
d/dt[s^2] = d/dt[x^2 + y^2]
d/dt[s^2] = d/dt[x^2] + d/dt[y^2]
2s*ds/dt = 2x*dx/dt + 2y*dy/dt
2(25)*ds/dt = 2(15)*5 + 2(20)*(10)
50*ds/dt = 150 + 400
50*ds/dt = 550
ds/dt = 550/50
ds/dt = 11
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Side note: The information t = 40 is never used. It's just extra info.
Your question is somewhat ambiguous.
If you want to solve this equation for y in terms of x, first multiply all of its terms by the LCD (which is 5), to remove the fractions.
5(3/5)x + 5(1.4y) = 5(2/5)
Then 3x + 7y = 2 This is the equation of the line in "standard form."
Next, subtract 3x from both sides: 7y = -3x + 2
Dividing by 7, y = (-3/7)x + (2/7)
This is the slope-intercept form of the given equation. It has a slope of -3/7 and a y-intercept of (0, 2/7).
The point-slope form of the same equation is
y- 2/7 = (-3/7)(x - 0), or -3x/7. y - 2/7 = (-3/7)x
The discontinuity occurs when the denominator is equal to zero, as it has "infinite" slope, and thus is not a real value or point.
x^2+x-12
x^2+4x-3x-12
x(x+4)-3(x+4)
(x-3)(x+4)
So discontinuities occur when x=-4 and x=3
Answer:
x°=180-45-60=75°is your answer