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Bumek [7]
3 years ago
10

Can someone help me answer this

Mathematics
2 answers:
VikaD [51]3 years ago
8 0
C



Your welcome lolololololol


Alexxandr [17]3 years ago
8 0
Answer: C

Explanation:
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​ Quadrilateral ABCD ​ is inscribed in this circle.
Ilya [14]
Hello,

When you have an inscribed quadrilateral, the opposite sides are supplementary.

So you can write and solve the following equation.
x + 6x + 19 = 180
7x + 19 = 180
7x = 161
x = 23

Now, plug in 23 for X and we will find the measurement of B.
6(23) + 19
138 + 19
157

The measure of angle B is 157 degrees. (The picture is not drawn to scale)

Good luck,
MrEQ
3 0
3 years ago
Edi;bbbbbbbbbbbbbbbbbbbb
marshall27 [118]
<h2><em><u>Answer:</u></em></h2><h2><em><u>Sorry i didn't understand the question but thank you for the points </u></em></h2><h2><em><u>Step-by-step explanation:</u></em></h2>

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3 0
2 years ago
HELP I WILL GIVE BRAINLIEST!!!
lys-0071 [83]

<em>T= 250 + 45a.</em>

<em>Since the cost of the medicine costs $250, and there is $45 dollars per appointment then 45 a would represent the 45 dollars for every appointment she chooses to have.</em>

<em>Hope this helps and have a nice day.</em>

<em>-R3TR0 Z3R0</em>

7 0
2 years ago
Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of
Alexxx [7]

Answer:

a) 0.018

b) 0            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)

= 1 - P(z \leq 2.1)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%

0.018 is the probability that if an individual man is randomly​ selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected​ men, these men have a mean hip breadth greater than 16.5 in)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(x > 16.5)  

P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)  

= 1 - P(z \leq 23.29)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 1 = 0

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0
3 years ago
What is 5
Sonja [21]

Answer:

A

Step-by-step explanation:

hope this helps:))

6 0
3 years ago
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