The probability that all of the next ten customers who want this racket can get the version they want from current stock is 0.821
<h3>How to solve?</h3>
Given: currently has seven rackets of each version.
Then the probability that the next ten customers get the racket they want is P(3≤X≤7)
<h3>Why P(3≤X≤7)?</h3>
Note that If less than 3 customers want the oversize, then more than 7 want the midsize and someone's going to miss out.
X ~ Binomial (n = 10, p = 0.6)
P(3≤X≤7) = P(X≤7) - P(X≤2)
From Binomial Table:
= 0.8333 - 0.012
= 0.821
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(x,y)=(64/81, 70/81) I can provide a description if needed. I used the process of elimination.
Answer:
12-x*3
Step-by-step explanation:
That is permuations
that would be 10! or 10*9*8*7*6*5*4*3*2*1=3628800 ways
Answer:
(-3,-1)
Step-by-step explanation:
When you graph it on a graphing paper, you can see that the graph touches it but barely
