Someone help me please

Help me i need the answer

katovenus [111]

Answer:

its red

0 $\leq$ y $\leq$ 225

Step-by-step explanation:

6 0

3 years ago

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You make 10$ an hour babysitting and 20$ an hour lifeguard you need to make at least 120$ next week to buy a concert ticket you

Fynjy0 [20]

Answer:

Which of these sentences from the excerpt most strongly supports the correct answer to Question 5?

Answer choices for the above question

Quesiton 5 says

Which of these inferences about the author’s point of view is best supported by the entire excerpt?

From: The Immortal Life of Henrietta Lacks" lesson

A. “She’s simply called HeLa, the code name given to the world’s first immortal human cells—her cells, cut from her cervix just months before she died.”

B. “I’ve spent years staring at that photo, wondering what kind of life she led, what happened to her children, and what she’d think about cells from her cervix living on forever—bought, sold, packaged, and shipped by the trillions to laboratories around the world.”

C. “One scientist estimates that if you could pile all HeLa cells ever grown onto a scale, they’d weigh more than 50 million metric tons—an inconceivable number, given that an individual cell weighs almost nothing.”

D. “All of the stories mentioned that scientists had begun doing research on Henrietta’s children, but the Lackses didn’t seem to know what that research was

Step-by-step explanation:

Which of these sentences from the excerpt most strongly supports the correct answer to Question 5?

Answer choices for the above question

Quesiton 5 says

Which of these inferences about the author’s point of view is best supported by the entire excerpt?

From: The Immortal Life of Henrietta Lacks" lesson

A. “She’s simply called HeLa, the code name given to the world’s first immortal human cells—her cells, cut from her cervix just months before she died.”

B. “I’ve spent years staring at that photo, wondering what kind of life she led, what happened to her children, and what she’d think about cells from her cervix living on forever—bought, sold, packaged, and shipped by the trillions to laboratories around the world.”

C. “One scientist estimates that if you could pile all HeLa cells ever grown onto a scale, they’d weigh more than 50 million metric tons—an inconceivable number, given that an individual cell weighs almost nothing.”

D. “All of the stories mentioned that scientists had begun doing research on Henrietta’s children, but the Lackses didn’t seem to know what that research was

5 0

3 years ago

1plss help, its time

DanielleElmas [232]

Answer:

60 degrees

Step-by-step explanation:

Similar shapes have the same angles but different side lengths.

8 0

2 years ago

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If we are given x such that 25^x-9^y=18 and 5^x-3^y=3, compute 5^x+3^y.

leonid [27]

25 = 5*5 and 9 = 3*3, which we can exploit to write

$25^x-9^y=(5^2)^x-(3^2)^y=5^{2x}-3^{2y}=(5^x)^2-(3^y)^2$

so that this expression is actually a difference of squares. We can factorize this to get

$(5^x-3^y)(5^x+3^y)=18$

and given that $5^x-3^y=3$ , we divide both sides by this to get

$5^x+3^y=\dfrac{18}3=\boxed{6}$

7 0

3 years ago

We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c

Kisachek [45]

We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

$\frac{dT}{dt}=k(T-a)$

We now separate the time and the temperature variables as follows,

$\frac{dT}{T-a}=kdt$

Integrating both sides of the differential equation, we obtain;

$ln(T-a)=kt +c$

This natural logarithmic equation can be rewritten as;

$T-a=e^{kt +c}$

Applying the laws of exponents, we obtain,

$T-a=e^{kt}\times e^{c}$

$T-a=e^{c}e^{kt}$

We were given the initial conditions,

$T(0)=4$

Let us apply this condition to obtain;

$4-20=e^{c}e^{k(0)}$

$-16=e^{c}$

Now our equation, becomes

$T-a=-16e^{kt}$

or

$T=a-16e^{kt}$

When we substitute a=20,
we obtain,

$T=20-16e^{kt}$

b) We were also given that,

$T(5)=8$

Let us apply this condition again to find k.

$8=20-16e^{5k}$

This implied

$-12=-16e^{5k}$

$\frac{-12}{-16}=e^{5k}$

$\frac{3}{4}=e^{5k}$

We take logarithm to base e of both sides,

$ln(\frac{3}{4})=5k$

This implies that,

$\frac{ln(\frac{3}{4})}{5}=k$

$k=-0.2877$

After 15 minutes, the temperature will be,

$T=20-16e^{-0.2877\times 15}$

$T=20-0.21376$

$T=19.786$

After 15 minutes, the temperature is approximately 20°C

6 0

3 years ago