6j + 1/3n = 134...multiply by 3....18j + n = 402
1/3j + n = 31....multiply by 3....j + 3n = 93
the multiplying by 3 is optional...I just did it because it is easier to work with equations when there are no fractions.
18j + n = 402....multiply by -3
j + 3n = 93
----------------
-54j - 3n = - 1206 (result of multiplying by -3)
j + 3n = 93
----------------add
-53j = - 1113
j = -1113/-53
j = 21
j + 3n = 93
21 + 3n = 93
3n = 93 - 21
3n = 72
n = 72/3
n = 24
so Jasons collection (j) consists of 21 books and Nathans collection (n) consists of 24 books
To solve this, you need to make the amount they built on Monday and the amount they built on Tuesday compatible with each other so you can add them together to subtract that amount from 4.
Start by multiplying 1/2 by 3, and 1/3 by 2.
This gives you 3/6 and 2/6. Now add them together:
3/6 + 2/6 = 5/6
Finally, subtract this amount from 4:
4 - 5/6 = 3 1/6 (19/6 works too)
Hope this helps! :)
This is all I got sorry if it don’t help
Its would be orange because only two people liked it out of all the kids asked.