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RSB [31]
3 years ago
14

How many whole numbers are there with not more than 4 digits IF YOU PUT A LINK OR UNHELPFUL ANSWER I WILL REPORT I WILL GIVE BRA

INLIEST
Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer:

There are 9,999 positive whole numbers with 4 or less digits or less and one whole number which is neither positive nor negative.

This gives us 9,999+9,999+1 or 19,999 , whole numbers composed of 4 digits or less.

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Solve for t. 6t plus 5t equals negative 11
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Answer:

t = -1

Step-by-step explanation:

6t + 5t = -11

11t = -11

t = -1

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What is 24% as a fraction?
IgorLugansk [536]

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Read 2 more answers
How do you solve this problem
Kryger [21]

Answer:

sin(A) = \frac{21}{{29} }

cos(A)=\frac{20}{29 }

tan(A)=\frac{21}{20}

sin(C) = \frac{20}{{29} }

cos(C)=\frac{21}{29 }

tan(C)=\frac{20}{21}

Step-by-step explanation:

So first we need to make sure we know the trig identities to solve this problem.

  • sin(\alpha )=\frac{opposite}{hypotenuse}
  • cos(\alpha )=\frac{adjacent}{hypotenuse}
  • tan(\alpha )=\frac{opposite}{adjacent}

Here we only have two legs of the triangle, so we will need to use the Pythagorean Theorem a² + b² = c² to solve for the missing leg, the hypotenuse in this case.

  • Solving for the hypotenuse, c, we get c = \sqrt{a^{2} +b^{2} }
  • Here a = 20 and b = 21, so plugging in these values to the equation we get: c= \sqrt{(20)^{2}+(21)^{2}  } =\sqrt{400+441} =\sqrt{841}=29

Now we can use the trig identities to figure out the missing values for the problem

  • sin(A) = \frac{21}{{29} }
  • cos(A)=\frac{20}{29 }
  • tan(A)=\frac{21}{20}
  • sin(C) = \frac{20}{{29} }
  • cos(C)=\frac{21}{29 }
  • tan(C)=\frac{20}{21}
4 0
3 years ago
I added question and example. answer it CORRECTLY and you will get brainliest!
snow_lady [41]

Answer:

1008

Step-by-step explanation:

like the 2nd picture we split it in 3 rectangular prism

V_{1}=6*7*8=336

V_{2}=6*7*8=336

V_{3}=6*7*8=336

V=336+336+336=1008

5 0
3 years ago
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