Answer: Last option is true,
Step-by-step explanation: All other option are false
Answer:
<h3><u>Option 1</u></h3>
Earn $50 every month.
- Let x = number of months the money is left in the account
- Let y = the amount in the account
- Initial amount = $1,000

This is a <u>linear function</u>.
<h3><u>Option 2</u></h3>
Earn 3% interest each month.
(Assuming the interest earned each month is <u>compounding interest</u>.)
- Let x = number of months the money is left in the account
- Let y = the amount in the account
- Initial amount = $1,000

This is an <u>exponential function</u>.
<h3><u>Table of values</u></h3>
<u />

From the table of values, it appears that <u>Account Option 1</u> is the best choice, as the accumulative growth of this account is higher than the other account option.
However, there will be a point in time when Account Option 2 starts accruing more than Account Option 2 each month. To find this, graph the two functions and find the <u>point of intersection</u>.
From the attached graph, Account Option 1 accrues more until month 32. From month 33, Account Option 2 accrues more in the account.
<h3><u>Conclusion</u></h3>
If the money is going to be invested for less than 33 months then Account Option 1 is the better choice. However, if the money is going to be invested for 33 months or more, then Account Option 2 is the better choice.
Lia=L
Phil=12.80+L
Cam=3L
L+12.80+L+3L=200.30
5L+12.80=200.30
5L=200.30-12.80
5L=187.5
L=187.5/5
Plug into the equations at the top
L=Lia=$37.5
Phil=12.80+37.5=$50.30
Cam=3(37.5)=$112.50
I did part of it but the rest idk sorry
Answer:
When the graph has a horizontal line.
Step-by-step explanation:
Zero rate of change. When the value of increases, the value of remains constant. That is, there is no change in value and the graph is a horizontal line.
SOURCE: GOOGLE