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Ivanshal [37]
3 years ago
10

Write a real world scenario in which 12 fluid ounces would need to be converted into liters . Then make the conversion . Use 1 f

l oz = 0.0296 l. Round your answer to the nearest tenth
Mathematics
1 answer:
Airida [17]3 years ago
6 0
Real life scenario:
Lily in New York calls her friend in Germany and wants to tell her she has a new fish tank that can fit in 12 fluid ounces.

Her friend asks her how much it is in liters:
12*0.0296=0.3552.

It's a very tiny tank!
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What is the solution to the system of equations ?
Fudgin [204]

Answer:

A solution to a system of equations means the point must work in both equations in the system. So, we test the point in both equations. It must be a solution for both to be a solution to the system. Hope this helps.

7 0
3 years ago
Read 2 more answers
HELP PLEASE PICTURE EXPLAINS EVERYTHING!!!!
allochka39001 [22]

Answer:

(a) Slope of Line 1 = 3

    Slope of Line 2 = 3

    Slope of Line 3 = -1/3

(b)

Line 1 and Line 2 = Parallel

Line 1 and Line 3 = Perpendicular

Line 2 and Line 3 = Perpendicular

Step-by-step explanation:

Please mark as brainliest! Thanks! Hope this helps!

4 0
3 years ago
The Ferris wheel has a radius of 70 feet. The distance between the wheel and the ground is 4 feet. The rectangular coordinate sy
Leya [2.2K]

Answer:

The equation of the circular wheel is x^2+(y-74)^2=(70)^2.

Step-by-step explanation:

Given :

Radius of Ferris wheel r = 70 feet.

The distance between the wheel and the ground = 4 feet.

Also, the rectangular coordinate system shown has its origin on the ground directly below the center of the wheel.

So the x coordinate of center of wheel must  be 0 , and y coordinate = 70 + 4 = 74

Thus, Coordinates of center = (0,74)

The equation of circle is given by :-

(x-h)^2+(y-k)^2=r^2

Now center (h,k) = (0,74) and r = 70 , we get

x^2+(y-74)^2=(70)^2

Hence, the equation of the circular wheel is x^2+(y-74)^2=(70)^2.

6 0
3 years ago
1. Find four consecutive even integers such that the sum of the first and third is 6 less than the largest
Sophie [7]

These are indeed quite a lot of exercises, but a lot of them are almost identical - only small computations will change. So, I'm glad to help you with one exercise from every cathegory, but I encourage you to solve the others on your own.

<h2>Exercise 1</h2>

You can call four consecutive integers as

x,\ x+1,\ x+2,\ x+3

So, the sum of the first and third is x+(x+2) = 2x+2

We want this quantity to be six less than the largest, i.e. (x+3)-6 = x-3

So, the equality is

2x+2 = x-3

Subtract x from both sides:

x+2 = -3

Subtract 2 from both sides:

x = -5

So, the consecutive integers are

-5,\ -4,\ -3,\ -2

In fact, the sum of the first and third is -5-3 = -8, which is indeed six less than the largest: -8 = -2-6

<h2>Exercise 2</h2>

If you call the first odd number x, the next consecutive odd numbers will be x,\ x+2,\ x+4,\ x+6

In fact, we have to count skipping two's, because we only want odd integers. From here, you go on like exercise 1: you write the largest (which is x+6), and set it to be two more than the sum of the other three (x, x+2 and x+4)

<h2>Exercise 3</h2>

By the same logic of exercise 2, two consecutive even integers are x,\ x+2, assuming that x is even.

So, you set the equation as usual: the smaller (which is x) is 26 less than three times the larger (which means 3(x+2)-26)

<h2>Exercise 4 to 8</h2>

These are all pretty identical to exercise 1: you start by listing three or four consecutive integers:

x,\ x+1,\ x+2\quad\text{or}\quad  x,\ x+1,\ x+2\ x+3

and then you translate the request of each exercise accordingly. Remember that expressions like "three times the second number" means that you have to multiply: 3(x+1), while expression like "six more than the first" or "thirteen less than the first" imply adding/subtracting: x+6 or x-13.

<h2>Exercise 9</h2>

A multiple of 5 can be written as 5k, for some integer k.

So, three consecutive multiples of 5 are

5k, 5(k+1), 5(k+2) = 5k, 5k+5, 5k+10

We want these three numbers to have a sum of 75. So, we have

5k, 5k+5, 5k+10 = 75 \iff 15k+15 = 75 \iff 15k = 60 \iff k = 4

So, the three numbers are

5k, 5(k+1), 5(k+2) = 5\cdot 4, 5\cdot 5, 5\cdot 6 = 20, 25, 30

3 0
3 years ago
I need help -45=-155+x
viktelen [127]

Answer:

x = 110

Step-by-step explanation:

8 0
3 years ago
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