Answer:
B. Group 17
Explanation:
The element is Bromine. Its electron configuration is:
1s2 2s2p6 3s2p6d10 4s2p5
You can see that its last orbital is 4p^5 for 5 electrons in the 4p orbital.
Answer:
≈ 708
Explanation
Here we have equation as:
4 Al + 3 O₂ → 2 Al₂O₃
As we know:
No of moles = Mass/ Molar mass
Here, Mass is 375 g and Molar mass is 27 gms, so no. of moles of Al will be:
=375 g /27 g/mol
= 13.889 mol
About mole ratio, we can see that for 4 moles of Al , 2 moles of Al2O3 are formed, so for 13.889 moles of Al, 13.889 mol ÷ 2 =6.944 moles of Al₂O₃ will be formed.
As we know:
Mass= No of moles/Molar mass
Mass of Al₂O₃ = 6.944 mol × 102 g/mol
= 708.288 g
Hope it helps!
Kilograms is the SI unit for mass
Answer:
Explanation:
destroyerplayz20062
13 hours ago
Chemistry
High School
Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)
destroyerplayz20062
13 hours ago
Chemistry
High School
Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)
destroyerplayz20062
13 hours ago
Chemistry
High School
Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)
destroyerplayz20062
13 hours ago
Chemistry
High School
Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)
