Please help this is due today

Kathleen makes iced coffee by adding ice to her room temperature coffee in a glass. What statement explains what is taking place

Ganezh [65]

Answer:

The answer is the heat is transferred from the ice to the coffee.

Explanation:

Hot molecules tend to transfer to colder molcules, which causes the ice to melt and makes the coffee colder.

Hope this helps! :)

3 0

1 year ago

Suppose you mix one mole of sulfuric acid (H2SO4) with 1 mole of sodium hydroxide(NaOH).

olasank [31]

Answer & Explanation:

The neutralization of H₂SO₄ with NaOH is occurred according to the balanced equation:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O,

It is clear that every 1.0 mol of H₂SO₄ needs 2 mol of NaOH to be neutralized completely.

So, when you mix one mole of sulfuric acid with 1 mole of sodium hydroxide, there will be an excess of sulfuric acid.

Thus, the pH of the solution remain below 7.

7 0

3 years ago

1. Starting with 9.3 moles of O 2 , how many moles of H 2 S will be needed and how many moles of SO 2 will

enyata [817]

Answer:

Moles of H₂S needed = 6.2 mol

Moles of SO₂ produced = 6.2 mol

Explanation:

Given data:

Number of moles of O₂ = 9.3 mol

Moles of H₂S needed = ?

Moles of SO₂ produced = ?

Solution:

Chemical equation:

2H₂S + 3O₂ → 2SO₂ + 2H₂O

Now we will compare the moles of oxygen with H₂S.

O₂ : H₂S

3 : 2

9.3 : 2/3×9.3 = 6.2 mol

Now we will compare the moles of SO₂ with both reactant.

O₂ : SO₂

3 : 2

9.3 : 2/3×9.3 = 6.2 mol

H₂S : SO₂

2 : 2

6.2 : 6.2 mol

So 6.2 moles of SO₂ are produced.

6 0

3 years ago

Which statement is true about a liquid but not a gas?

vovangra [49]

Answer:

I think its D

Explanation:

.........................

3 0

2 years ago

Read 2 more answers

Determine the equilibrium constant, Kp, for the following reaction, by using the two reference equations below: 2 NO(g) + O2(g)

klio [65]

Answer:

$Kp=3.07x10^6$

Explanation:

Hello,

In this case, by knowing the given reference reactions, one could rearrange them as follows:

$2 NO(g) \leftrightarrow N_2(g) + O_2(g); Kp_2 = \frac{1}{2.3 x 10^{-19}}=4.35x10^{18}$

$N_2(g) + 2O_2(g) \leftrightarrow 2NO_2(g);Kp_3=(8.4x10^{-7})^2=7.056x10^{-13}$

Subsequently, to obtain the main reaction, we add the aforementioned reference rearranged reactions as shown below (just as reference):

$2NO(g)+N_2(g)+2O_2\leftrightarrow 2NO_2(g)+N_2+O_2$

Consequently, the equilibrium constant is computed as:

$Kp=\frac{[N_2][O_2]}{[NO]^2} * \frac{[NO_2]^2}{[N_2][O_2]^2} =Kp_2*Kp_3=4.35x10^{18}*7.056x10^{-13}=3.07x10^6$

Best regards.

8 0

3 years ago