A negative ΔH and ΔS suggests that the reaction is exothermic and the leads to a decrease in the entropy of the system. In this case, the spontaneity of the reaction depends on the temperature and reaction is spontaneous at low temperature and non-spontaneous at a high temperature.
Answer: The atomic orbitals which combine to form molecule is 5p-orbitals and the noble gas is Xenon (Xe).
Explanation: Iodine is the 53rd element of the periodic table. It lies in Group 17 of the periodic table.
Valence shell electronic configuration of Iodine =
5p orbitals of two iodine atoms overlap to share one electron each. The total number of electrons that each iodine atom contain are 53. Each iodine atom shares one electron with the other iodine atom, so that each molecule of contains 54 electrons. Hence, the electronic configuration of noble gas Xenon is same as the each iodine atom in molecule.
Therefore, 5p orbital overlap to form molecule and the noble gas having same number of electrons as each iodine atom in molecule is Xenon. the symbol for this gas is 'Xe'.
Answer:
Explanation:
Remark
First of all you have to identify what is happening. You make the following observations.
The solution in the test tube in a cold water bath is colorless.
As you add heat, the color changes from colorless to brown.
What you are told
N2O4 is colorless
NO2 is brownish red.
What you conclude
The reaction is endothermic. That means it requires heat to happen. An endothermic reaction is
A + Heat ===> B
So you have three possible correct answers
N2O4 + 14 kCal ===> 2NO2
N2O4 ====> 2NO2 dH = 14 kCal
N2O4 ====> 2NO2 - 14 kCal
I can't read the last 4 equations.
Other answers
As the temperature increased, the N2O4 became less.
As the temperature increased, the products were favored. (color change)
The reaction is exothermic (gives off heat) when the reaction goes from
NO2 - Heat ===> N2O2
Answer:
its not actually proven its just a hypothesis because they can't dig that deep because of the pressure