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Nikolay [14]
2 years ago
15

9. t An element that has only 5 electrons in the 4p orbital is located in which group? A. O Group 1 B. Group 17 C. O Group 2 D.

Group 8​
Chemistry
1 answer:
umka2103 [35]2 years ago
6 0

Answer:

B. Group 17

Explanation:

The element is Bromine. Its electron configuration is:

1s2 2s2p6 3s2p6d10 4s2p5  

You can see that its last orbital is 4p^5 for 5 electrons in the 4p orbital.

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And I don't exactly get what you are trying to ask hit me back up though
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Determine the number of bonding electrons and the number of nonbonding electrons in the structure of SI2. Enter the number of bo
mariarad [96]

Answer:

4, 16,

Explanation:

SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).

Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.

7 0
3 years ago
A material has a volume of 63.0 cm3 and a mass of 28 grams.  What is the density of the material in g/cm3 to the correct number
dimaraw [331]

Answer:

0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).

Explanation:

  • Knowing that:

<em>d = m/V,</em>

where, d is the density of the material (g/cm³).

m is the mass of the material (m = 28 g).

V is the volume of the material (V = 63.0 cm³).

<em>∴ d = m/V </em>= (28 g)/(63.0 cm³) = <em>0.4444 g/cm³ ≅ 0.44 g/cm³ (2 significant figures).</em>

7 0
3 years ago
What are the seismic waves that travel along earth’s surface and produce the most severe ground movements?
stellarik [79]
The answer is surface waves.
5 0
3 years ago
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Calculate the enthalpy of the reaction below (∆Hrxn, in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g).
nalin [4]

The enthalpy change of the reaction below (ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

The bond energies data is given as follows:

BE  for C≡O  = 1072 kJ/mol

BE for Cl-Cl = 242 kJ/mol

BE for C-Cl = 328 kJ/mol

BE for C=O = 766 kJ/mol

The enthalpy change for the reaction is given as :

ΔHr×n = ∑H reactant bond - ∑H product bond

ΔHr×n = ( BE C≡O + BE Cl-Cl) - ( BE C=O + BE 2 × Cl-Cl )

ΔHr×n = ( 1072 + 242 ) - ( 766 + 656 )

ΔHr×n = 1314 - 1422

ΔHr×n = - 108 kJ

Thus, The enthalpy change of the reaction below ( ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

To learn more about enthalpy here

brainly.com/question/13981382

#SPJ1

7 0
1 year ago
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