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denis-greek [22]
3 years ago
5

De 1 280 alumnos que tiene una escuela, 1 088 salieron de excursión, ¿qué porcentaje

Mathematics
1 answer:
NeTakaya3 years ago
5 0

Usando el concepto de porcentaje, se encuentra que 15% faltaron, opcion D.

------------------

La porcentage de una medida a sobre un total b es dada por:

P = \frac{a}{b} \times 100\%

------------------

En esta pregunta, tenemos que

  • Total de 1280 alumnos, o sea b = 1280.
  • 1088 salieron, entonces, 1280 - 1088 = 192 faltaron, o sea, a = 192.

La porcentaje dos que falton es de:

P = \frac{192}{1280} \times 100\% = 15\%

O sea, la respuesta correcta es dada por opcion d.

Se da un problema similar en brainly.com/question/24554492

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The following graphs show the performance of two stocks over the first five months of the year. A graph titled Stock A B C has m
hichkok12 [17]

Answer:

C) Stock XYZ shows the best performance. The scale of Stock XYZ makes the graph appear to be rising more slowly.

Step-by-step explanation:

i did this question on my test, from reading the graph, i am almost certain this is the answer. correct me if i am wrong!

8 0
2 years ago
Read 2 more answers
This is the pond in a shape of a prism, it is completely full of water. Colin uses a pump to empty the pond. The level goes down
AnnZ [28]

Answer:

150 minutes

Step-by-step explanation:

P.S - The exact question is -

Given - This is the pond in a shape of a prism, it is completely full of

             water. Colin uses a pump to empty the pond. The level goes

             down by 20 cm in the first 30 min.

To find - Work put how many minutes Colin has to wait for the pond

               to completely empty.

Proof -

Given that,

Height of prism = 1 m

Also,

Base of the prism is trapezium and

Sides of the trapezium are 0.6 m and 1.4 m

Height of trapezium is 2 m

We know that,

Area of trapezium = \frac{1}{2}× (sum of sides)× height

                             =  \frac{1}{2}× (0.6 + 1.4)× 2

                             =  \frac{1}{2}× (2)× 2

                             =  2 m²

⇒Area of trapezium = 2 m²

Now,

Volume of prism = Area of trapezium × height of prism

                          = 2 m² × 1 m

                          = 2 m³

⇒Volume of prism = 2 m³

Now,

Given that the level goes down by 20 cm in the first 30 min

We know

100 cm = 1 m

⇒1 cm = \frac{1}{100} m = 0.01 m

⇒20 cm = 20×0.01 m = 0.2 m

⇒The level goes down by 0.2 m in the first 30 min.

Also,

we know that height of water = height of prism = 1 m

So, the remaining water left in the pond = 1 m - 0.2 m = 0.8 m

Also,

Volume of Remaining water = Area of trapezium × height

                                           = 2 m² × 0.8 m

                                           = 1.6 m³

⇒Volume of Remaining water = 1.6 m³

Now,

Volume of emptied water = Total Volume - Volume of Remaining water

                                       = 2 m³ - 1.6 m³

                                       = 0.4 m³

⇒Volume of emptied water = 0.4 m³

Now,

0.4 m³ water will be empty in 30 minutes

⇒ 1 m³ water will be empty in \frac{30}{0.4} = 75 minutes

⇒1.6 m³ water will be empty in 1.6 × 75 = 120 minutes

∴ we get

The remaining water is empty in 120 minutes

So,

Total pond is empty in 120 + 30 minutes

⇒Total pond is empty in 150 minutes

5 0
2 years ago
Solve the polynomial inequality x^2-3x-10>0
djverab [1.8K]

As x² - 3x - 10 factors, we can use the zero product property and pull it apart into factors. It factors because 2 and 5 have a difference of 3 and product of 10

x² - 3x - 10 > 0

(x - 5)(x + 2) > 0

To find where the inequality is true, we use a sign test. When x-5 > 0, it means x >5, and 5 is one of our sign test values. Similarly, -2 is the other. We can then make three intervals - A (less than -2), B (between -2 and 5), and C (more than 5).

<--------------- -2 ------------------ 5 -------------------------->

A B C

To do a sign test, we choose values to see what happens. First, test x = -5.

(-5 - 5)(-5 + 2) = (-10)(-3) = 30. Because 30 > 0, the inequality is true for x < -2. So interval A is true.

Next, test x = 0.

(0 - 5) (0 + 2) = (-5)(2) = -10. Because -10 < 0 is false, the inequality is false for x > -2 and x < 5. So interval B is false.

Last, test x = 10

(10 - 5) (10 + 2) = (5) (8) = 40. Because 40 > 0 is true, the inequality is true for x > 5. So interval C is true.

We put the true intervals together.

(-∞, -2) ∪ (5, ∞) is where this inequality is true,

{x : x < -2 or x > 5} is also how it's said in set notation.

7 0
3 years ago
Find the area. simply your answer <br><br> 2x<br> 3x
Firdavs [7]
The area of a triangle is always:

A=bh/2  (base times the height divided by 2)

A=3x(2x)/2

A=6x^2/2

A=3x^2

...


7 0
3 years ago
Read 2 more answers
WILL GIVE BRAINEST <br><br>Let f(x)=7x-4<br><br>what is f(6)<br><br>a.48<br>b.42<br>c.38<br>d.46
Sever21 [200]
F(6) = 7(6) - 4

f(6) = 42 - 4

f(6) = 38

Hope this helps!
4 0
3 years ago
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