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satela [25.4K]
3 years ago
9

Find the value of each expression using the given information cot∅=8, csc<0 find sin ∅

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

9514 1404 393

Answer:

  sin(∅) = -√65/65

Step-by-step explanation:

The identities that relate the cotangent, the cosecant, and the sine are ...

  csc² = 1 +cot²

  sin = 1/csc

_____

For the given values, we find ...

  csc(∅)² = 1 +cot(∅)² = 1 +8² = 65

  csc(∅) = -√65 . . . . . . . . . . . . . . . . square root with attention to sign

  sin(∅) = -1/√65 = (-√65)/65

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LoJao(37-3八):log 20 (3rniay)
Amanda [17]
Hello,
if the question is to solve the equation:

1) log must exist:
a)==>2r²-27>0==>(r-√(27/2))(r+√(27/2))==> outside the roots
r<-√(27/2) or r>√(27/2)
b)==>3r²+12r>0 ==>3r(r+4)>0 ==>outside the roots
r>0 or r<-4
==>r<-4 or r>√(27/2)=3.6742...

If this is realized:
2r-27=3r²+12r
==>r²+12r+27=0
Δ=12²-4*27=36=6²
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One solution r=-9

Proof
 log_{20}(2*(-9)^2-27)= log_{20}135

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7 0
4 years ago
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