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satela [25.4K]
3 years ago
9

Find the value of each expression using the given information cot∅=8, csc<0 find sin ∅

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

9514 1404 393

Answer:

  sin(∅) = -√65/65

Step-by-step explanation:

The identities that relate the cotangent, the cosecant, and the sine are ...

  csc² = 1 +cot²

  sin = 1/csc

_____

For the given values, we find ...

  csc(∅)² = 1 +cot(∅)² = 1 +8² = 65

  csc(∅) = -√65 . . . . . . . . . . . . . . . . square root with attention to sign

  sin(∅) = -1/√65 = (-√65)/65

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Please explain your answer. THX!
Elden [556K]

Answer:

see explanation

Step-by-step explanation:

(3)

Given cosΘ = - \frac{4}{5}

Then by Pythagoras' theorem the third side is 3 ( 3,4, 5 triangle )

Since Θ in second quadrant then sinΘ > 0

sinΘ = \frac{3}{5}

Using the trigonometric identity

sin2Θ = 2sinΘcosΘ, then

sin2Θ = 2 × \frac{3}{5} × - \frac{4}{5} = - \frac{24}{25}

(4)

Using the trigonometric identity

cos(x - y) = cosxcosy + sinxsiny

note cos15° = cos(45 - 30)°

cos(45 - 30) = cos45cos30 + sin45sin30

                    = ( \frac{\sqrt{2} }{2} × \frac{\sqrt{3} }{2}) + (\frac{\sqrt{2} }{2} × \frac{1}{2})

                    = \frac{\sqrt{2(\sqrt{3}+1) } }{4}

         

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3 years ago
Can somebody plz help?
Natalija [7]

Answer:

what do you need I'm not the smartest person but I may be able to help :)

6 0
3 years ago
Read 2 more answers
Is 8/10 mile longer than 1/2
seropon [69]
Yes because if you find common denominators (in this case, "10") you would have to compare 8/10 to 5/10. 8>5 so 8/10 is longer than 1/2.
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Answer:

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3 0
3 years ago
In a restaurant, the proportion of people who order coffee with their dinner is p. A simple random sample of 144 patrons of the
mote1985 [20]
<h2>Answer with explanation:</h2>

Given : In a restaurant, the proportion of people who order coffee with their dinner is p.

Sample size : n= 144

x= 120

\hat{p}=\dfrac{x}{n}=\dfrac{120}{144}=0.83333333\approx0.8333

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-

Null hypothesis : H_0: p\geq0.85   [ it takes equality (=, ≤, ≥) ]

Alternative hypothesis : H_1: p  [its exactly opposite of null hypothesis]

∵Alternative hypothesis is left tailed, so the test is a left tailed test.

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.83-0.85}{\sqrt{\dfrac{0.85(1-0.85)}{144}}}\\\\=-0.561232257678\approx-0.56

Using z-vale table ,

Critical value for 0.05 significance ( left-tailed test)=-1.645

Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.

Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.

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