Answer:
a) 0.25
b) 52.76% probability that a person waits for less than 3 minutes
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:

In which
is the decay parameter.
The probability that x is lower or equal to a is given by:

Which has the following solution:

The probability of finding a value higher than x is:

In this question:

a. Find the value of λ.

b. What is the probability that a person waits for less than 3 minutes?

52.76% probability that a person waits for less than 3 minutes
Answer:
It is the first answer you got it right
Step-by-step explanation:
Step-by-step explanation:
Yessss
To round it would be 0-4 you keep the same # 5-up so in this case it would be 12 ,