Question

The table below shows the distance d(t) in meters that an object travels in t seconds: t (seconds) d(t) (meters) 3 126 4 224 5 350 6 504 What is the average rate of change of d(t) between 3 seconds and 5 seconds, and what does it represent?

Answer 1

90 m/s; it represents the average speed of the object between 2 seconds and 4 seconds, and here's why:

the main formula is v= D / Dt,  D=Dfinal - Dinitial
                                                    Dt= tfinal - tinitial


so between t=2 and t= 4, V = 240-60/ 4-2= 90m/s