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Westkost [7]
2 years ago
14

Picture shown. what is the volume of the rectangular pyramid?

Mathematics
1 answer:
klasskru [66]2 years ago
5 0

Answer:

answer is 187.2

Step-by-step explanation:

5.2 times 4 times 9= 187.2

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1) The graph of a bicycle ramp contains the points (-6,0) and (3,3). What is 5 points
lianna [129]

Answer:

\frac{1}{3}

Step-by-step explanation:

It was given that, the graph of the bicycle ramp contains the points (-6,0) and (3,3).

We want to find the slope.

We use the formula:

m =  \frac{y_2-y_1}{x_2-x_1}

We substitute the points into the formula to get;

m =  \frac{3 - 0}{3 -  - 6}

m =  \frac{3}{3 + 6}

Add in the denominator

m =  \frac{3}{9}  =  \frac{1}{3}

The slope of the ramp is 1/3.

6 0
3 years ago
If my car has 19 seats 6 are full what is left
Zarrin [17]
19 - 6 = 12

You will have 12 seats left
4 0
3 years ago
Read 2 more answers
PLEASE HELP ANSWER THIS QUESTION!!!
rewona [7]

Answer:

about 64.03

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
You are designing a rectangular poster to contain 7575 in2 of printing with a 33​-in margin at the top and bottom and a 11​-in m
erma4kov [3.2K]

Answer:

The dimensions of the rectangular poster is 15 in by 5 in.

Step-by-step explanation:

Given that, the area of the rectangular poster is 75 in².

Let the length of the rectangular poster be x and the width of the rectangular poster be y.

The area of the poster = xy in².

\therefore xy=75

\Rightarrow y=\frac{75}{x}....(1)

1 in margin at each sides and 3 in margin at top and bottom.

Then the length of printing space is= (x-2.3) in

                                                           =(x-6) in

The width of printing space is = (y-2.1) in

                                                  =(y-2) in

The area of the printing space is A =(x-6)(y-2) in²

∴ A =(x-6)(y-2)

Putting the value of y

\Rightarrow A =(x-6)(\frac{75}{x}-2)

\Rightarrow A = 87-\frac{450}{x}-2x

Differentiating with respect to x

A '= \frac{450}{x^2}-2

Again differentiating with respect to x

A''=-\frac{900}{x^3}

To find the minimum area of printing space, we set A' = 0

\therefore \frac{450}{x^2}-2=0

\Rightarrow 450 =2x^2

\Rightarrow x^2=225

\Rightarrow x=\pm 15

Now putting x=±15 in A''

A''|_{x=15}=-\frac{900}{15^3}

A''|_{x=-15}=-\frac{900}{(-15)^3}=\frac{900}{(15)^3}>0

Since at x=15 , A"<0 Therefore at x=15 , the area will be minimize.

From (1) we get

y=\frac{75}{x}

Putting the value of x

y=\frac{75}{15}

   =5 in

The dimensions of the rectangular poster is 15 in by 5 in.

4 0
3 years ago
Which expression is equivalent to -5(m - 3)?<br> -5(-3 + m)<br> 15m - 5<br> -5(-3m)<br> -3(m - 5)
Zepler [3.9K]

Answer:

the first one

Step-by-step explanation:

The first equation is -5m+15

and the first one is 15-5m

Which is basically the same thing.

Glad to help

6 0
3 years ago
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