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NNADVOKAT [17]
2 years ago
9

omar will donate up to $500 to charity. the money will be divided between two charities: the city of youth fund and educational

growth foundation. omar would like the amount donated to the educational growth foundation to be at least four times the amount donated to the city youth fund. Let X denote the amount of money ( in dollars ) donated to the city youth fund. let Y denote the amount of money ( in dollars ) donated to the educational growth foundation. shade the region corresponding to all values of X and Y that satisfy the requirements.
Mathematics
1 answer:
marshall27 [118]2 years ago
6 0

Answer:

Please refer to the attached graph

Step-by-step explanation:

Knowing the following:

X = amount of money donated to the city youth fund

Y = amount of money donated to the educational growth foundation

We can write the statements in form of equations:  

"Will donate up to $500, the money will be divided between two charities"

(a) X + Y = \$ 500

"The amount donated to the educational growth foundation to be at least four times the amount donated to the city youth fund"

(b) Y \geq 4X

If we graph both equations we can see the area where both conditions are met (see graph attached)

Where the blue line is (a) and the red line is (b)

Shaded area represent all the possible solutions for the donations, for example:

X=100 and Y=400 or

X=50 and Y=200, etc.

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Anarel [89]

Answer:

B) 9

Step-by-step explanation:

110 + 75 + 11x - 9 + 8x + 13 = 360

19x + 189 = 360

19x (+ 189 - 189) = 360 - 189

19x = 171

19x/19 = 171/19

x = 9

3 0
3 years ago
Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.
k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = \frac{3}{4},

q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28

       = 6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28

       = (\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28

       = (\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}

       = -\frac{1666}{64}

       = -\frac{833}{32} ≠ 0

Therefore, Yuri is not correct. x = \frac{3}{4} can not be a root of the given expression.

6 0
3 years ago
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Two coins, A and B, each have a side for heads and a side for tails. When coin A is tossed, the probability it will land tails-s
BlackZzzverrR [31]

Answer:

Is the number of tosses for each coin enough for the sampling distribution of the difference in sample proportions PA-PB to be approximately normal?

b. No, 20 tosses for coin A is enough, but 20 tosses for coin B is not enough.

Step-by-step explanation:

a) Data and Calculations:

The probability of coin A landing tails-side up = 0.5

The proportion of times coin A lands tails-side up (PA) = 20 * 0.5 = 10

Therefore, the probability of coin A landing heads-side up = 0.5 (1 - 0.5)  

And the proportion of times that coin A lands heads-side up = 20 * 0.5 = 10.  

The proportion on either side is equally distributed.

This is why 20 tosses for coin A is enough, since the sample proportions PA is approximately normal, symmetric, and equally distributed.  There will be equal amounts of 10 tosses (0.5 *20) for either heads-side up or tails-side up.

For coin B, the probability of landing tails-side up = 0.8

The proportion of times coin B lands tails-side up (PB) = 20 * 0.8 = 16

Therefore, the probability of coin B landing heads-side up = 0.2 (1 - 0-.8)

The proportion on either side is not equally distributed, but skewed.

This is why 20 tosses for coin B is not enough, since the sample proportions PB is not approximately normal, symmetric, and equally distributed.  There will be 16 tosses landing tails-side up (0.8*20) and only 4 tosses landing heads-side up (0.2*20).

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Muplication of fractions explain
Verizon [17]
Multiplication of fractions is multiplying fractions<span />
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3 years ago
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These cones are similar. Find the volume
kotegsom [21]

Answer:

Hight = 22 cm

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Step-by-step explanation:

<em>Finding the Hight of The Red Cone(</em><em>Check the Image</em><em>)</em>

<em>Volume of The Blue Cone(</em><em>Check Image Below</em><em>)</em>

<em></em>

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