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DIA [1.3K]
3 years ago
11

Please help! This question has to do with "Similar Figures".

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0

Answer:

Do not help her she is toxic

Step-by-step explanation:

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Determine if the data comes from a linear function or an exponential function. Then, enter
svet-max [94.6K]

1.  The data is not linear.  There's not a constant difference between the f(x) values.  (AKA there's not a fixed slope between the data points)

2. The data is exponential, because there's a consistent ratio in the f(x) values:

     189/567 = 1/3

     63/189 = 1/3

     21/63 = 1/3

     7/21 = 1/3

Each new y-value (aka f(x)-value) is 1/3 the previous value.

Also, f(0)=567.

If we put that together, we have f(x) = 567 (1/3)^x.

8 0
3 years ago
____% of 50 = 30<br> Please help
aleksandr82 [10.1K]

Answer:

60%

Step-by-step explanation:

30 is 60 percent of 50

5 0
3 years ago
Read 2 more answers
What is the name of the shape graphed by the function r^2=9 cos(2 theta)?
Lady bird [3.3K]

<span>The name of the shape graphed by the function r ^ 2 = 9 cos (2 theta) is called the “<u>lemniscate</u>”. A lemniscate is a plane curve with a feature shape which consists of two loops that meet at a central point. The curve is also sometimes called as the lemniscate of Bernoulli. </span>


Explanation:

The period of coskθ is 2π/k. In this case, k = 2 therefore the period is π.

r ^ 2 = 9 cos 2θ ≥0 → cos 2θ ≥0. So easily one period can be chosen as θ ∈ [0, π] wherein cos 2θ ≥0.

As cos(2(−θ)) = cos2θ, the graph is symmetrical about the initial line.

Also, as cos (2(pi-theta) = cos 2theta, the graph is symmetrical about the vertical θ = π/2

A Table for half period [0,π4/] is adequate for the shape in Quarter1

Use symmetry for the other three quarters:

(r, θ) : (0,3)(3/√√2,π/8)(3√2/2,π/6)(0,π/4<span>)</span>

5 0
3 years ago
Which expression is equivalent to Negative 32 Superscript three-fifths?
Sidana [21]

Answer:

-8

Step-by-step explanation:

Given: (-32)^{(\frac{3}{5}) }

To choose: the correct option

Solution:

Power refers to a number of times, a number is multiplied by itself. Another name for power is exponent.

As per rule of exponents, (a^m)^n=a^{mn}

Here,

(-32)=(-2)^5

Therefore,

(-32)^{(\frac{3}{5}) }=[(-2)^5]^{(\frac{3}{5}) }=(-2)^{5(\frac{3}{5}) }

Here, a=-2,m=5,n=\frac{3}{5}

So,

(-32)^{(\frac{3}{5}) }=[(-2)^5]^{(\frac{3}{5}) }=(-2)^{5(\frac{3}{5}) }=(-2)^3=-8

8 0
3 years ago
Read 2 more answers
2/3=z-6/15 solve the proportion.
Aleksandr-060686 [28]
2/3 = (z - 6) / 15
cross multiply
3(z - 6) = 2(15)
3z - 18 = 30
3z = 30 + 18
3z = 48
z = 48/3
z = 16 <===
7 0
4 years ago
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