1. The data is not linear. There's not a constant difference between the f(x) values. (AKA there's not a fixed slope between the data points)
2. The data is exponential, because there's a consistent ratio in the f(x) values:
189/567 = 1/3
63/189 = 1/3
21/63 = 1/3
7/21 = 1/3
Each new y-value (aka f(x)-value) is 1/3 the previous value.
Also, f(0)=567.
If we put that together, we have f(x) = 567 (1/3)^x.
Answer:
60%
Step-by-step explanation:
30 is 60 percent of 50
<span>The name of the shape graphed by the function r ^ 2 = 9
cos (2 theta) is called the “<u>lemniscate</u>”. A lemniscate is a
plane curve with a feature shape which consists of two loops that meet at a
central point. The curve is also sometimes called as the lemniscate of
Bernoulli. </span>
Explanation:
The
period of coskθ is 2π/k. In this case, k = 2 therefore the
period is π.
r ^ 2 = 9 cos 2θ ≥0 → cos 2θ ≥0. So easily
one period can be chosen as θ ∈
[0, π] wherein cos 2θ ≥0.
As cos(2(−θ)) = cos2θ, the graph is symmetrical about the initial line.
Also,
as cos (2(pi-theta) = cos 2theta, the graph is symmetrical about the
vertical θ = π/2
A
Table for half period [0,π4/] is
adequate for the shape in Quarter1
Use symmetry for the other three quarters:
(r, θ) : (0,3)(3/√√2,π/8)(3√2/2,π/6)(0,π/4<span>)</span>
Answer:
Step-by-step explanation:
Given: 
To choose: the correct option
Solution:
Power refers to a number of times, a number is multiplied by itself. Another name for power is exponent.
As per rule of exponents, 
Here,
Therefore,
![(-32)^{(\frac{3}{5}) }=[(-2)^5]^{(\frac{3}{5}) }=(-2)^{5(\frac{3}{5}) }](https://tex.z-dn.net/?f=%28-32%29%5E%7B%28%5Cfrac%7B3%7D%7B5%7D%29%20%7D%3D%5B%28-2%29%5E5%5D%5E%7B%28%5Cfrac%7B3%7D%7B5%7D%29%20%7D%3D%28-2%29%5E%7B5%28%5Cfrac%7B3%7D%7B5%7D%29%20%7D)
Here, 
So,
![(-32)^{(\frac{3}{5}) }=[(-2)^5]^{(\frac{3}{5}) }=(-2)^{5(\frac{3}{5}) }=(-2)^3=-8](https://tex.z-dn.net/?f=%28-32%29%5E%7B%28%5Cfrac%7B3%7D%7B5%7D%29%20%7D%3D%5B%28-2%29%5E5%5D%5E%7B%28%5Cfrac%7B3%7D%7B5%7D%29%20%7D%3D%28-2%29%5E%7B5%28%5Cfrac%7B3%7D%7B5%7D%29%20%7D%3D%28-2%29%5E3%3D-8)
2/3 = (z - 6) / 15
cross multiply
3(z - 6) = 2(15)
3z - 18 = 30
3z = 30 + 18
3z = 48
z = 48/3
z = 16 <===
