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3 years ago

2. How many moles of scandium atoms are in 5.3 x 1025 atoms of scandium?

Chemistry

1 answer:

MrRissso [65]3 years ago

6 0

Number of moles of Scandium atoms=88

<h3>Further explanation</h3>

Given

5.3 x 10²⁵ atoms of scandium

Required

number of moles

Solution

<em>1 mol = 6.02 x 10²³ particles(molecules, atoms, ions)</em>

<em /> $\tt N=n\times No(No=Avogadro's)\\\\n=\dfrac{N}{No}\\\\n=\dfrac{5.3.10^{25}}{6.02.10^{23}}=88.04\approx=88~moles$ <em />

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2 years ago

Read 2 more answers

Make the following conversions. Show your calculations.

Natalija [7]

Answer:

1. 500 cm = 5 m

2. 1000 g = 1 kg

3. 455 L = 45, 500 cL

4. 0.865 m = 0.00865 m or 8.65 * 10^-3 n

5. 33.5 cm = 335 mm

6. 0.0198 m = 19800 micrometers

7. 57.65 cg = 5.765 * 10^8 nanograms

8. 1000 L = 1 kl

9. 99 degrees F = 37.222 degrees C

Explanation:

1. One meter = 100 centimeters

500 centimeters/ 100 centimeters = 5 meters

2. One kilogram = 1000 grams.

1000 grams/1000 grams = 1 kilogram

3. One Liter = 100 centiliters

455 liters * 100 centiliters = 45, 500 centiliters

4. One meter = 100 centimeters

0.865 centimeters/100 centimeters = 0.00865 meters

5. One centimeter = 10 millimeters

33.5 centimeters * 10 millimeters = 335 millimeters

6. One meter = 1.0 * 10^6 micrometers

0.0198 meters * 1 * 10^6 micrometers = 19800 micrometers.

7. One centigram = 1.0 * 10^7 nanograms

57.65 centigrams * 1 * 10^7 nanograms = 5.765 * 10^8 nanograms.

8. One kiloliter = 1000 L

1000 L/ 1000 L = 1 kiloliter

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5/9(67) = x

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4 years ago

Rank the following substances based on the forces present in each molecule from weakest to strongest - Cl2 , LiF , OF2 , CH4 , N

solniwko [45]

Answer:

c12, ch4, of2, lif, nh3

Explanation:

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4 years ago

How many moles are in 2.98 E 28 molecules of water?

jek_recluse [69]

The number of moles : n = 4.95 x 10 ²⁴

<h3>Further explanation</h3>

Given

2.98E28 molecules of water

Required

The number of moles

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

n = N : No

n = 2.98 x 10²⁸ : 6.02.10²³

n = 4.95 x 10 ²⁴

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3 years ago