Mol sulfuric acid = 19 g * (1 mol) / (98.1 g) = 0.19367 mol
mol H2O = 0.19367 mol H2SO4 * (2 H2O) / (1 H2SO4)
= 0.387359 mol H2O
grams H2O = 0.387359 mol H2O * (18 g)/(1 mol)
= 6.97 g
The answer is 7.0 grams of water
Answer:
Caesium
down the group atomic radius increases and along period wise atomic radius decreases
Answer:
A. 15859.2 L or 15900 L
B. 0.629 mol
Explanation:
At STP, one mole is equal to approximately 22.4 L
L or mL is volume, so you are attempting to solve for L or mL.
A.
708 mol x (22.4 L/1 mol) = 15859.2 L (w/ significant figures included - 15900 L)
B.
(14.1 L) x (1 mole/ 22.4 L) = 0.629 mol.
Answer:
Metal (appropriate charge on metal) nonmetal-ide
Explanation:
1) Write the name of transition metal as shown on the Periodic Table.
2) Write the name and charge for the non-metal.
Use the total charge on the non-metal (or polyatomic ion) find the charge on the transition metal.
3) After the name for the metal, write its charge as a Roman Numeral in parentheses. Example: Iron (II) chloride.
