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2 years ago

Solve the equation by completing the square (x+2)(x-3)=(x-3)

Mathematics

1 answer:

elena-14-01-66 [18.8K]2 years ago

4 0

The answer:
X1 = -1 X2 = 3
Explanation: Down the images

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find two numbers such that the sum of twice the first and thrice the second is 92 ,and four times the first exceeds seven times

Ilia_Sergeevich [38]

Answer:

First number = 25

Second number = 14

Step-by-step explanation:

Let the numbers be x & y

The sum of twice the first and thrice the second is 92

2x + 3y = 92 -------------------(I)

Four times the first exceeds seven times the second by 2

4x - 7y = 2 --------------------(II)

Multiply equation (I) by -2 and then add the equations

(I)*-2 -4x - 6y = -184

(II) 4x - 7y = 2 { Now add, thus x will be eliminated}

- 13y = -182 {Divide both sides by -13}

y = -182/-13

y = 14

Plugin the value of y in equation (I)

2x + 3*14 = 92

2x + 42 = 92

2x = 92 - 42

2x = 50

x = 50/2

x = 25

First number = 25

Second number = 14

7 0

3 years ago

The circumference of my circle is 45 inches. What is the diameter

romanna [79]

Answer:

14.32 inches to nearest thousandth.

Step-by-step explanation:

Circumference = π * d where d = the diameter.

So 45 = π * d

d = 45 / π

= 14.32 inches

8 0

3 years ago

Read 2 more answers

Help me plssssssssssssssss I need help

RUDIKE [14]

Answer:

Step-by-step explanation:

the answer is 5.75, but when rounded off, it will become 5

8 0

2 years ago

Read 2 more answers

An urn contains 5 red balls and 2 green balls. Two balls are drawn one after the other. What is the probability that the second

AleksAgata [21]

Answer:

The probability that the second ball is red is 71%

Step-by-step explanation:

Probabilities

We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).

The first ball can be red (R) or green (G). The probability that it's red is computed by

$\displaystyle P(R)=\frac{5}{7}$

The probability is's green is computed by

$\displaystyle P(G)=\frac{2}{7}$

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

$\displaystyle P(RR)=\frac{5}{7}\cdot \frac{4}{6}=\frac{10}{21}$

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

$\displaystyle P(GR)=\frac{2}{7}\cdot \frac{5}{6}=\frac{5}{21}$

The total probability of the second ball being red is

$\displaystyle P(XR)=\frac{10}{21}+\frac{5}{21}=\frac{5}{7}=0.71$

The probability that the second ball is red is 71%

7 0

3 years ago

What is the answer so pwease help

bezimeni [28]

U see I would help but just because u said “pwease” I’m not :)

4 0

2 years ago