Answer:
69 <-- quotient
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Step-by-step explanation:
8)555
48
--
75
72
--
3 <-- remainder
Answer:
The statement is true.
Step-by-step explanation:
Let us assume that x is the required number.
Now, given that the number minus 3 is at most 12.
Hence, x - 3 ≤ 12
⇒ x ≤ 15 ......... (1)
And also given that 1 more than 2 times the number is at least 25.
Hence, 2x + 1 ≥ 25
⇒ 2x ≥ 24
⇒ x ≥ 12 .......... (2)
Therefore, from equations (1) and (2) we get the number must be greater than or equal to 12 or less than or equal to 15.
So, the statement is true. (Answer)
Answer:
1) Arithmetic since it decreases by 3 so, -3n + 38.
2) Arithmetic since it decreases by 20 each time, so -20n+17
Step-by-step explanation:
Answer:
-10/3 is the answer
Step-by-step explanation:
Given are two complex numbers as
Recall Demoivre theorem as
(cosA+isinA)(cos A+isin B) = cos(A+B)+isin(A+B)
Hence here we have sum of angles as
A+B = 63+117 =180
=
Since sin180=0 and cos 180=-1
A = event the person got the class they wanted
B = event the person is on the honor roll
P(A) = (number who got the class they wanted)/(number total)
P(A) = 379/500
P(A) = 0.758
There's a 75.8% chance someone will get the class they want
Let's see if being on the honor roll changes the probability we just found
So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).
---------------
A and B = someone got the class they want and they're on the honor roll
P(A and B) = 64/500
P(A and B) = 0.128
P(B) = 144/500
P(B) = 0.288
P(A | B) = P(A and B)/P(B)
P(A | B) = 0.128/0.288
P(A | B) = 0.44 approximately
This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.
Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.
Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.
