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sleet_krkn [62]
3 years ago
12

Which of the relations below is a function?Group of answer choices{(2,3), A(3,4), (5,1), (6,2), (2,4)B}{(2,3), (3,4), (5,1), (6,

2), (7,3)}C{(2,3), (3,4), (5,1), (6,2), (3,3)}
Mathematics
1 answer:
lbvjy [14]3 years ago
5 0

Answer:

its c

Step-by-step explanation:

because, if you liike closely you can see in your lession that its rlly tiny but its the answer

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Which statement is true about the slope of the graphed line?
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Answer:

c

Step-by-step explanation:

because I had a test on these

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Use the quadratic formula to find the solutions to the quadratic equation below 2x^2-5x+5=0
Serggg [28]

Answer:

x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

Step-by-step explanation:

Solve for x:

2 x^2 - 5 x + 5 = 0

Hint: | Using the quadratic formula, solve for x.

x = (5 ± sqrt((-5)^2 - 4×2×5))/(2×2) = (5 ± sqrt(25 - 40))/4 = (5 ± sqrt(-15))/4:

x = (5 + sqrt(-15))/4 or x = (5 - sqrt(-15))/4

Hint: | Express sqrt(-15) in terms of i.

sqrt(-15) = sqrt(-1) sqrt(15) = i sqrt(15):

Answer: x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4

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4 years ago
What is the vertex of the quadratic function f(x)=x2+6x+16? Write your answer
Olenka [21]

Answer:

The vertex of the quadratic function is:

(x_{v}, y_{v})=\left(-3,\:7\right)

Step-by-step explanation:

Given the function

f\left(x\right)=x^2+6x+16

As the vertex of the form y=ax^2+bx+c is defined as:

x_v=-\frac{b}{2a}

As the quadratic function of parabola params are

a=1,\:b=6,\:c=16

so

x_v=-\frac{b}{2a}

x_v=-\frac{6}{2\cdot \:1}

x_v=-3

Putting x_v=-3 to determine y_v

y_v=\left(-3\right)^2+6\left(-3\right)+16

y_v=3^2-18+16

y_v=9-2

y_v=7

Therefore, the vertex of the quadratic function is:

(x_{v}, y_{v})=\left(-3,\:7\right)

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