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3 years ago

Help I’m super confused and help would be appreciated!

Mathematics

1 answer:

meriva3 years ago

6 0

Answer: 50 degrees

Step-by-step explanation: the total degree is 90 90-40=50

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Solve the differential equation. y' + 5xey = 0.

galben [10]

Answer:

The solution is $y = - ln(\frac{5}{2}x^{2} + C)$

Step-by-step explanation:

To solve the differential equation, we will find $y$

From the given equation, y' + 5xey = 0.

That is, $y' + 5xe^{y} = 0$

This can be written as

$\frac{dy}{dx} + 5xe^{y} = 0$

Then,

$\frac{dy}{dx} = - 5xe^{y}$

$\frac{dy}{e^{y}} = - 5x dx$

Then, we integrate both sides

$\int {\frac{dy}{e^{y}}} =\int {- 5x dx}$

$\int {e^{-y}dy }} =\int {- 5x dx}$

Then,

$-e^{-y} = -\frac{5}{2}x^{2} + C$

$e^{-y} = \frac{5}{2}x^{2} + C$

Then,

$ln(e^{-y}) = ln(\frac{5}{2}x^{2} + C)$

Then,

$-y = ln(\frac{5}{2}x^{2} + C)$

Hence,

$y = - ln(\frac{5}{2}x^{2} + C)$

5 0

3 years ago

A 2-column table with 7 rows. Column 1 is labeled Power of 3 with entries 3 cubed, 3 squared, 3 Superscript 1, 3 Superscript 0,

Masja [62]

Answer:

a=1, b=1/3, c=1/27

Step-by-step explanation:

The table is given below:

$\left|\begin{array}{c|c}$Powers of 3&Value\\----&---\\3^3&27\\3^2&9\\3^1&3\\3^0&a\\3^{-1}&b\\3^{-2}&\frac{1}{9} \\3^{-3}&c\end{array}\right|$

(a)As the exponents decrease, the next term is gotten by a division of the previous term by 3.

$f_n=f_{n-1}\div 3$

(b)

$f_n=f_{n-1}\div 3\\I.a=f_n, f_{n-1}=3,\\a=f_n=3\div 3=1\\II. b=f_n, f_{n-1}=1,\\b=f_n=1\div 3=\frac{1}{3}\\III. c=f_n, f_{n-1}=\frac{1}{9},\\c=f_n=\frac{1}{9}\div 3=\frac{1}{27}$

a=1, b=1/3, c=1/27

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tino4ka555 [31]

Step-by-step explanation

i don't understand option B

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Solve the following equation: 3x+2=2x-6

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Answer:x=-8

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