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3 years ago

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Please help!!!!!!!!!!!!!!!! Jeremiah is saving money in a bank account. He opened the account with $25. Each month he adds the s

ame amount of money to the
account. After 8 months, the account has $505. Which equation can be used to calculate the amount of money the account, y, and after x
months?
Answer choices :
A.y=8x+25
B.y=25x
C.y=25x+505
D.60x+25

1 answer:

NikAS [45]3 years ago

7 0

Answer:

a.)

Step-by-step explanation:

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3x+1 = y 2x+3y = 14<br> please explain the steps if you can as well

Likurg_2 [28]

3x + 1 = y
2x + 3y = 14

To solve this system of equations, we are going to use the substitution method. Substitution the equation where the variable is isolated into the second equation. In this system of equations, y is isolated, so we will replace y in the second equation with 3x + 1.

2x + 3y = 14
2x + 3(3x + 1) = 14
2x + 9x + 3 = 14
We will add the like terms and subtract 3 from both sides of the equation.
11x + 3 = 14
11x = 11
x = 1
In this system of equations, x is equal to 1. Now we will go back and solve for y, plugging in 1 for x.
3(1) + 1 = y
2(1) + 3y = 14

3 + 1 = y
2 + 3y = 14

4 = y
3y = 2

4 = y
4 = y

The solution to this system of equations is (1, 4).

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Answer:

I think they are asking the area of the triangle so we are going with that.

Step-by-step explanation:

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8 x 4 = 32

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Which of these strategies would eliminate in the system of equations?<br> x-2y=11<br> 5x+3y=-11

fredd [130]

Answer:b

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Professor Isaac Asimov was one of the most prolific writers of all time. Prior to his death, he wrote nearly 500 books during a

svp [43]

Answer:

Step-by-step explanation:

n = sample size = 5

a) Let us determine the sum

$\sum x_i= 100+200+300+400+490=1490$

$\sum x_i^2= 100^2+200^2+300^2+400^2+490^2=540100$

$\sum y_i = 237+350+419+465+507=1978$

$\sum y_i^2= 237^2+350^2+419^2+465^2+507^2=827504$

$\sum x_i y_i=100 \times 237 + 200\times350+300 \times 419 + 400 \times 465 + 490 \times 507=653830$

Now we can determine $S_x_x, S_x_y, S_y_y$

$S_x_x = \sum x_i^2-\frac{(\sum x_1)^2}{n} \\= 540100 - \frac{1490^2}{5} \\= 96080$

$S_x_y = \sum x_i y_i -\frac{(\sum x_i)(\sum y_i) }{n} \\\\$

$653830 - \frac{1490 \times 1978 }{5} = 64386$

$S_y_y = \sum y_i^2-\frac{(\sum y_i)^2 }{n} = 82750-\frac{1978^2}{5} \\\\= 45007.2$

The estimate b of the slope β is the ratio of $S_x_y$ and $S_x_x$

$b = \frac{S_x_y}{S_x_x}$

$\frac{64386}{96080} = 0.67$

The mean is the sum of all value divide by number of values

$\bar x= \frac{\sum x_i}{n} \\\\= \frac{100+200+300+400+490}{5} \\\\= \frac{1490}{5} = 298$

$\bar y= \frac{\sum y_i}{n} \\\\= \frac{237+350+419+465+507}{5} \\\\= \frac{1978}{5} = 395.6$

The estimate a of the intercept is

$a = \bar y - b \bar x$

$= 395.6 - 0.69 \times 298\\= 195.9$

General least square equation;

$\bar y = \alpha + \beta x$

replace alpha by a = 3 and beta by b = 0.67 in general least equation

y = a + bx

195.9 + 0.67x

b)

<em>Scatter plot is shown in the attached file</em>

x is on the horizontal axis

y is n the vertical axis

The degree of freedom of regression is 1

because we use one variable s predictor variable

$d_f_R = 1$

The degree of freedom of error is the sample size n decrease by 2

$d_f_E =n-2= 5 - 2=3$

Total df is equal to the sum of seperate degree of freedom dfR and dfE

total df = 1 +3 4

$SSR = \frac{(S_x_y)^2}{S_x_x} = \frac{64386^2}{96080} \\\\= 43146.9296$

Total SS =Syy= 45007.2

SSE + Total SS = SSR

= 45007.2 - 43146.9296

= 1860.2705

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3 years ago