Answer:
The critical value is T = 1.895.
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 8 - 1 = 6
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.895, which is the critical value.
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159
The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
Answer:
T can be equal to 1 1/10 or 1.1 or 11/10
Step-by-step explanation:
10t=11
So divide by 10 on both sides.
t=11/10 which can be simplified to t=1 1/10 or t=1.1
:)
Use Pythagoras theorem
25^2 = 24^2 + x^2
x^2 = 25^2 - 24^2
x^2 = 49
x = 7 feet Answer
Answer:
C
Step-by-step explanation:
11 times 4 is 44 plus 5 is 49
Answer:
Part A- The 1st box is 96 and the second box is 10.
PartB-
Part C-
Step-by-step explanation:
<h2><u><em>
Part A:</em></u></h2>
5x12=60
6x12=72
8x12=96
10x12=120
So the 1st box is 96 and the second box is 10.
<h2><u><em>
Part B:</em></u></h2>
5 $50
6 $60
8 $80
I know this because Harry receives $10 per hour so you have to multiply the number of hours by $10.
<h2>
<em><u>Part C:</u></em></h2>
If Harry babysits for 5 hours, he would receive $60 but if he does yard work for 5 hours, he would receive $50. Harry would receive $10 more by babysitting than by doing yard work.
Hoped this helped.