Answer:
116
Step-by-step explanation:
8.2 / 2 = 4.1
a = 
0.5 x 8.2 x 5.6736 = 23.2618
23.2618 x 5 = 116.309 = 116
So basically sam split the 1000 to 2 groups so we have 1000 ÷ 2
now the first group divided the 500 (since 1000÷ 2 is 500) among five children so it would be 500 ÷ 5 which equals 100 per child and the second group divided their 500 between to boys, so you would get 500÷2 which is 250
so for group one it would be: 1000÷2÷5 which equals 100 per child and the second group is 1000÷2÷2 which equals 250 for each brother
Question:
A sample of cans of peaches was taken from a warehouse, and the content of each can mearsed for weight. the sample means was 486g with stand deviation 6g. state the weight percentage of cans with weight:
Draw normal curve to help - split into 8 section ( i can't draw it here)
a) 34.13% of cans will be between 480g and 486g.
b) 13.59 + 2.15 + 0.13= 15.87% of cans greater than 492g.
Look at the Stand Dev Graph where the give you the number
Step-by-step explanation:
Let me give you a different question and i will answer it, which you help you answer your question.
Solution :
Let 
and 
represents the proportions of the seeds which germinate among the seeds planted in the soil containing 
and 
mushroom compost by weight respectively.
To test the null hypothesis 
against the alternate hypothesis 
.
Let 
denotes the respective sample proportions and the 
represents the sample size respectively.
The test statistic can be written as :
which under 
follows the standard normal distribution.
We reject at 
level of significance, if the P-value 
or if 
Now, the value of the test statistics = -1.368928
The critical value = 
P-value = 
= 0.171335
Since the p-value > 0.05 and 
, so we fail to reject at level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the 
of the seeds that 
with the percent of the 
in the soil.
