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stiks02 [169]
3 years ago
5

y = 4x + 3 y = - 1 4 x - 5 What is the BEST description for the lines represented by the equations? A) horizontal B) intersectin

g C) parallel D) perpendicular
Mathematics
2 answers:
storchak [24]3 years ago
8 0
It is B. Because perpendicular is opposite reciprocal
adoni [48]3 years ago
7 0

Answer:

D. perpendicular

Step-by-step explanation:

You might be interested in
Find the midpoint of (8, –9) and (0,5).
finlep [7]

Answer:

M =( 4 , -2 )

Enjoy your day

8 0
3 years ago
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

8 0
3 years ago
PLEASE HELP IM ON A TIME LIMIT :(
Mice21 [21]

Answer:

hey hope this helps

<h3 /><h3>Comparing sides AB and DE </h3>

AB =

\sqrt{ {1}^{2} +  {1}^{2}  }

=  \sqrt{2}

DE

= \sqrt{ {(3 - 5)}^{2} +  {(1 + 1}^{2}  }  \\   = \sqrt{ {( - 2)}^{2}  +  {(2)}^{2} }  \\    = \sqrt{4 + 4}  \\  =  \sqrt{8}  \\   = 2 \sqrt{2}

So DE = 2 × AB

and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.

<u>scale factor</u> = AB/DE

= 2

It's been reflected across the Y-axis

<em>moved thru the translation of 3 units towards the right of positive x- axis </em>

for this let's compare the location of points B and D

For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3

so the triangle has been shifted by 3 units across the positive x axis

7 0
2 years ago
Some1 help me this due tomorrow and in stressing out
Olenka [21]

Answer:

Step-by-step explanation:

So, as shown in the picture below, you first have to find the line y = -1. Then that’s what your going to reflect. Imagine that your making a print of it, that’s how you will reflect it. Imagine taking a piece of paper with that triangle on it and folding it along that line I drew in my picture (at y=-1). Hope that helped!

5 0
3 years ago
Give two ways to write each algebraic expression in words. 4+×
KATRIN_1 [288]

Answer:

the sum of 4 and a number

4 plus a number

4 0
3 years ago
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