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nexus9112 [7]
3 years ago
14

1/b+x=3b/2x^2 - 1/xbtw ^2 means square​

Mathematics
1 answer:
AlekseyPX3 years ago
8 0

Answer:

x =  \frac{ - 3b}{4}  \: or \: b

Step-by-step explanation:

\frac{1}{b + x}  =  \frac{3b}{2 {x}^{2} }  -  \frac{1}{x}

=  >  \frac{1}{b + x}  =  \frac{3b - 2x}{2 {x}^{2} }

=  > 2 {x}^{2}  = (b + x)(3b - 2x)

=  > 2 {x}^{2}  = 3 {b}^{2}  - 2bx + 3bx - 2 {x}^{2}

=  > 2 {b}^{2}  = 3 {b}^{2}  + bx - 2 {x}^{2}

=  > 3 {b}^{2}  + bx - 4 {x}^{2}  = 0

=  > 3 {b}^{2}  + 4bx - 3bx - 4 {x}^{2}  = 0

=  > b(3b + 4x) - x(3b + 4x) = 0

=  > (3b + 4x)(b - x) = 0

Hence,

x =  \frac{ - 3b}{4}  \: or \: b

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For the equation below, x is the input and y is the output. y = -4x + 3 If the input is -8, then the output is
KonstantinChe [14]

Answer:

35

Step-by-step explanation:

If is given the value -8 as it is the input then -->

y = -4(-8) + 3

Negative four times negative 8 is positive 32 so

y= 32 + 3

And 32 plus 3 is 35


7 0
3 years ago
Read 2 more answers
3 over 3 - square root 5
DIA [1.3K]

Answer:

-1.236.

Step-by-step explanation:

3/3 = 1.

√5 = 2.236.

1.000 - 2.236 = -1.236.

the answer is negative because the smaller number is subtracting the larger number..........u just subtract the normal way,( the larger number take away the smaller number), but u should insert a negative sign to the answer.

5 0
3 years ago
How do you solve this
alekssr [168]
5/(6x-2)=-1/(x+1)
You have to multiply both sides by the denominators so it becomes:
5*(x+1)=-1*(6x-2)
5x+5=-6x+2
3=x

This applies to the second one as well, if you need any more help, feel free to message me :)
8 0
4 years ago
Read 2 more answers
Show the processes for solving 2x+3y=5 and 4x - y=17 using elimination and substitution
r-ruslan [8.4K]

<u>ANSWER:  </u>

The solution of the two equations 2x+3y=5 and 4x - y=17 is (4, -1).

<u>SOLUTION: </u>

Given, two linear equations are 2x + 3y = 5 → (1) and 4x – y = 17 → (2).

Let us first solve the above equations using <em>elimination process. </em>

For elimination, one of the coefficients of variables has to be same in order to cancel them.

Now solve (1) and (2)

eqn (1) \times 2 → 4x + 6y = 10

eqn (2) → 4x – y = 17

(-) ----------------------------

     0x + 7y = -7

y = -1

Substitute y value in (2)

4 x-(-1)=17 \rightarrow 4 x+1=17 \rightarrow 4 x=17-1 \rightarrow 4 x=16 \rightarrow x=4

So, solution of two equations is (4, -1).

<u><em>Now let us solve using substitution process.</em></u>

Then, (2) → 4x – y = 17 → 4x = 17 + y → y = 4x – 17

Now substitute y value in (1) → 2x + 3(4x – 17) = 5 → 2x + 12x – 51 = 5 → 14x = 5 + 51 → 14x = 56  

x = 4

Substitute x value in (2) → y = 4(4) – 17 → y = 16 – 17 → y = -1

Hence, the solution of the two equations is (4, -1).

7 0
3 years ago
Help please ! i would appreciate <br> math
AveGali [126]

Answer:

no

Step-by-step explanation:

they over lap

8 0
3 years ago
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