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Natali5045456 [20]
3 years ago
12

In the equation e = 0.45d + 2 , what is the rate of change?

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
5 0
Don’t know.................
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Amy runs 5 miles in 38 minutes how many miles would she run in 57 minutes?
Len [333]
Amy runs 1 mile in 7.6 minutes so in 57 minutes she will have run 7.5 miles
5 0
3 years ago
Which of the following gives a valid reason for using the given solution method to solve the system of equations shown? Equation
alukav5142 [94]

Answer:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

Step-by-step explanation:

Equation I: 4x − 5y = 4

Equation II: 2x + 3y = 2

These equation can only be solved by Elimination method

Where to Eliminate x :

We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I

Hence:

Equation I: 4x − 5y = 4 × 2

Equation II: 2x + 3y = 2 × 4

8x - 10y = 20

8x +12y = 6

Therefore, the valid reason using the given solution method to solve the system of equations shown is:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

4 0
3 years ago
18.Lupe and her friends spent $20 on snack mix and water. They bought x bags of snack mix and y bottles of water. They bought a
Readme [11.4K]

Answer:

bags of snack = x = 6

bottles of water = y = 5

Step-by-step explanation:

The system of equations can be used to determine how many of each item they bought.

20.00=2.50x+1.00y

11=x+y

how many bags of snack mix did they buy?

Let

bags of snack = x

bottles of water = y

20.00 = 2.50x + 1.00y (1)

11 = x + y (2)

From (2)

x = 11 - y

Substitute x = 11 - y into (1)

20.00 = 2.50x + 1.00y

20.00 = 2.50(11 - y) + 1.00y

20.00 = 27.5 - 2.50y + 1.00y

20.00 - 27.5 = -2.50y + 1.00y

-7.5 = -1.5y

y = -7.5/-1.5

y = 5

Substitute y = 5 into (2)

11 = x + y

11 = x + 5

11 - 5 = x

x = 6

bags of snack = x = 6

bottles of water = y = 5

7 0
3 years ago
What is the solution of ?
Tanya [424]

Answer:

of what???????..???..

5 0
3 years ago
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
2 years ago
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