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3 years ago

Definition of sound waves

Chemistry

1 answer:

vitfil [10]3 years ago

7 0

Sound waves are waves of growing larger and smaller, making it seem elastic through substances, such as air.

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What is an acid according to Arrhenius?

MariettaO [177]

Hello there.

<span>What is an acid according to Arrhenius?

</span><span>b. a substance that is a hydrogen ion donor
</span>

3 0

3 years ago

Read 2 more answers

3. How many more troops did the Union states have than the Confederate states?

lions [1.4K]

At the beginning of the war the Northern states had a combined population of 22 million people. The Southern states had a combined population of about 9 million. This disparity was reflected in the size of the armies in the field. The Union forces outnumbered the Confederates roughly two to one.

Also this should be listed for history

3 0

3 years ago

Maya adds six grams of sugar to water bottle containing 14 g of warm water what is the total weight of the sugar and water

V125BC [204]

Answer:

20g

Explanation:

14g+6g=20g

4 0

2 years ago

Tokyo, Japan is 8817.6 km from california. How many milimeters is this? Answer in scientific notation.

Novosadov [1.4K]

8.8176*10^9
Hope this helps!

8 0

2 years ago

While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by

grin007 [14]

Answer:

$n_{C2H_5OH}^{eq}=14.234mol$

Explanation:

Hello,

In this case, the reaction is:

$C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH$

Thus, the law of mass action turns out:

$Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}$

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change $x$ result:

$[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol$

In such a way, the equilibrium constant is then:

$Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31$

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

$Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}} =20.31$

Thus, the second change, $x_2$ finally result (solving by solver or quadratic equation):

$x_2=1.234mol$

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

$n_{C2H_5OH}^{eq}=x+x_2=13mol+1.234mol\\n_{C2H_5OH}^{eq}=14.234mol$

Best regards.

5 0

3 years ago