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Verdich [7]
3 years ago
7

I dont know how to put 2x(x + 5) in expanded form

Mathematics
2 answers:
Bond [772]3 years ago
8 0
(X+X+X) + (
X+X+X+X+X+X+X+X+X+X+X+X)
GaryK [48]3 years ago
3 0

Answer:

10 x + 2 x^2

Step-by-step explanation:

Expand the following:

2 x (x + 5)

Hint: | Distribute 2 x over x + 5.

2 x (x + 5) = 2 x×5 + 2 x x:

2 x×5 + 2 x x

Hint: | Multiply 2 and 5 together.

2×5 = 10:

10 x + 2 x x

Hint: | Combine products of like terms.

2 x x = 2 x^2:

Answer: 10 x + 2 x^2

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Step-by-step explanation:

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3 years ago
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What is the prime number ot 35,69,89,90
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The prime number will be 69 and 89
3 0
3 years ago
The sum of two numbers is 72 and their difference is 26. find two numbers?
Archy [21]

9514 1404 393

Answer:

  23, 49

Step-by-step explanation:

Let s represent the smaller of the two numbers. Then the larger is s+26, and the sum is ...

  s + (s+26) = 72

  2s = 72 -26

  s = (72 -26)/2 = 23

Then the larger number is

  s +26 = 49

The two numbers are 23 and 49.

_____

The reason we wrote the solution this way is to show you that the smaller number is half the difference between the given sum (72) and difference (26). This is the generic solution to a "sum and difference" problem. The smaller number is always half the difference of the give sum and difference. (Similarly, the larger is always half the sum of the given sum and difference.)

That is, the two numbers are always half the sum ± half the difference:

  72/2 ± 26/2 = {36+13, 36-13} = {49, 23}

7 0
2 years ago
Which sequence are geometric?
tiny-mole [99]

Answer:

The second one

The third one.

The last one.

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
Find the sum of the arithmetic series given ai = 45, an = 85, and n = 5.
seraphim [82]

Answer:

C. 325.

Step-by-step explanation:

The last term a5 = 85

a1 = 45

Sum of n terms = n/2 (a1 + l)

So here we have n = 5, a1 = 45 and the last term l = 85

= (5/2)(45 + 85)

= 5/2 * 130

= 325.

5 0
3 years ago
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