Answer:
Peace is when people are able to resolve their conflicts without violence and can work together to improve the quality of their lives.
Answer:
Here are some other sentences which always demonstrate that perhaps the hospital operates with either the help of technology, which is given below.
Explanation:
- As eventually as he was acknowledged or confessed, the medical records of David would be documented by the medical practitioners.
- David was therefore positioned through an ICU during which his heart rate had been monitored closely (those same types of machinery were directly linked to the desktops in position to obtain comment of his vital statistics.)
<span>#include <iostream>
using namespace std;
bool bears(int n);
int main(){
int number;
do{
cout<<"enter the amount of bears (press 0 to stop the program): ";
cin>>number;
if (bears(number)){
cout<<"you have reached the goal!"<<endl;
}
else{
cout<<"sorry, you have not reached the goal."<<endl;
}
}while(number != 0);
}
bool bears(int n){
if (n < 42){
return false;
}
else if (n == 42){
return true;
}
else{
if (n % 5 == 0){
return bears(n - 42);
}
else if(n % 2 == 0){
return bears(n / 2);
}
else if(n % 4 == 0|| n % 3 == 0)
{
int one;
int two;
one=n%10;
two=(n%100)/10;
return bears(n - one * two);
}
}
<span>}</span></span>
Answer:
Stacy works as a Customer Service Representative.
Explanation:
Since Stacy uses coordination and communication, she would best fit the criteria for costumer service. A Customer Service Representative (CSR) helps customers out with questions about a business, including directions, finances, and other benefits of her company.
Explanation:
The program that merges two lists or two arrays is written below;
Code :
void main void
{
char [] arr1= {'1','2','3'};
char [] arr2= {'a','b','c','d','e'};
int l1= arr1.length;
int l2=arr2.length;
int l3=l1+l2;
char [] arr3=new char[l1+l2];
int i=0;
int j=0;
int k=0;
int m=0;
int r=0;
if(l1<l2)
r=l1;
else
r=l2;
while(m<r)
{
arr3[k++]=arr1[i++];
arr3[k++]=arr2[j++];
m++;
}
while(k<l3)
{
if(l1<l2)
arr3[k++]=arr2[j++];
else
arr3[k++]=arr1[i++];
}
for(int n=0;n<l3;n++)
{
System.out.print(arr3[n]+" ");
}
}
