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schepotkina [342]
3 years ago
9

Enzo is writing a paper about the similarities and differences between ancient Rome and modern America. Which text structure is

he most likely to use? problem and solution comparison and contrast chronological order order of importance I NEED HELP BAD IT IS TIMED
Computers and Technology
2 answers:
polet [3.4K]3 years ago
6 0

Answer:

The correct answer is compare and contrast.

GenaCL600 [577]3 years ago
4 0

Answer:

The correct answer is <em><u>B.) comparison and contrast</u></em>

Explanation:

just did the unit test review. you are welcome

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What is an objective of state-sponsored attackers?
Keith_Richards [23]

Answer:

The correct answer is 2. To Spy on citizens

Explanation:

State-sponsored attackers have particular objectives aligned with either the political, commercial or military interests of their country of origin. Investigation shows that “the reality is that if a determined, state-sponsored adversary wants your data, they’re going to get it unless another state-sponsored entity helps you defend it.”

7 0
3 years ago
When the increment or decrement operator is placed before the operand (or to the operand's left), the operator is being used in
Salsk061 [2.6K]

When the increment or decrement operator is placed before the operand (or to the operand's left), the operator is being used in prefix mode. Postfix mode on the other hand is when the increment or decrement operator is placed after the operand (or to the oper and's right) .


8 0
3 years ago
Which of the following is not regression test case? A. A representative sample of tests that will exercise all software function
AveGali [126]

Answer:

D. Low-level components are combined into clusters that perform a specific software sub-function

Explanation:

Normally, regression testing are done on a manual basis by simply re-executing a subset of the entire available test cases or it can be done automatically by utilizing playback tools or automated capture. Hence, from the options, a combination of low-level components into clusters that perform a specific sub-function does not align with how regression testing are done either manually or automatically.

6 0
3 years ago
When you are given a set of tables and asked to create a database to store their data, the first step is to ________?
Vlad1618 [11]
Scan   the tables  to make a digital copy of them
6 0
3 years ago
A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co
tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

                                                       = (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops                = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

     ∞                             n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

   = 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

6 0
3 years ago
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