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mezya [45]
3 years ago
9

triangle pqr is an iscosceles triangle with the coordinates p(2,3), q(5,10), and r(8,3). what is the area of triangle pqr ?

Mathematics
2 answers:
KatRina [158]3 years ago
8 0
I do not know i’m sorry.
never [62]3 years ago
4 0

Answer:

idek

Step-by-step explanation:

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Fully simplify using only positive exponents.
Assoli18 [71]

Answer:

\frac{xy^{3}}{25}

Step-by-step explanation:

Given

\frac{5x^6y^6}{125x^5y^3}

Required

Simplify the given expression

\frac{5x^6y^6}{125x^5y^3}

Start by applying law of indices

\frac{5x^{6-5}y^{6-3}}{125}

\frac{5xy^{3}}{125}

Divide numerator and denominator by 5

\frac{xy^{3}}{25}

Hence; the expression is equivalent to \frac{xy^{3}}{25}

6 0
3 years ago
$16.99 multiplied by 0.94 euro
Butoxors [25]
The answer is 15.9706
4 0
3 years ago
A children's inflatable pool takes 17 minutes to fill with an electric air pump. It takes 53 minutes to let the air out of the p
Molodets [167]

Answer:

less than 17 minutes

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP ASAP! BRAINLIEST TO BEST/RIGHT ANSWER
just olya [345]
Answer is D.




Tempted to give you my number for help.
6 0
4 years ago
Read 2 more answers
state whether the lines represented by the equations y=1/2x-1 and y+4=-1/2(x-2) are paraller, perdendicular, or neither
Brrunno [24]
The easiest way to tell whether lines are parallel, perpendicular, or neither is when they are written in slope-intercept form or y = mx + b. We will begin by putting both of our equations into this format.

The first equation, y =  \frac{1}{2}x - 1 is already in slope intercept form. The slope is 1/2 and the y-intercept is -1.

The second equation requires rearranging.
y + 4 =  -\frac{1}{2}(x - 2) \\ y + 4 = -\frac{1}{2}x + 1 \\ y = - \frac{1}{2} x- 3
From this equation, we can see that the slope is -1/2 and the y-intercept is -3.

When lines are parallel, they have the same slope. This is not the case with these lines because one has slope of 1/2 and the other has slope of -1/2. Since these are not the same our lines are not parallel.

When lines are perpendicular, the slope of one is the negative reciprocal of the other. That is, if one had slope 2, the other would have slope -1/2. This also is not the case in this problem.

Thus, we conclude that the lines are neither parallel nor perpendicular.
8 0
4 years ago
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