Sally has 600 ml of drink
Karen has 600 ml of lime juice
When it is mixed at a ratio of 2:7:3 . . .pineapple:orange:lime (respectively) . . this means . . . there are a total of 2 + 7 + 3 parts = 12 parts . . and each part individually is as follows:
pineapple = 2/12
orange = 7/12
lime = 3/12
Sally has 12 parts = 600 ml of drink
. . pineapple = 2/12*600ml = 100 ml pineapple
. . orange = 7/12*600ml = 350 ml orange
. . lime = 3/12*600ml = 150 ml lime
We know Karen has 600 ml of lime juice and if that is 3/12 of the total, then 600*12/3 = the total drink = 2400 ml of drink
Karen has 12 parts = 2400 ml of drink
. . pineapple = 2/12*2400ml = 400 ml pineapple
. . orange = 7/12*2400ml = 1400 ml orange
. . lime = 3/12*2400ml = 150 ml lime
Thus . . . (for Karen) . . .
<u><em>A = 2400 ml of drink</em></u>
<u><em>B = 400 ml of orange juice</em></u>
<u><em>C = 1400 ml of pineapple juice</em></u>
Answer:
B
Step-by-step explanation:
11 13 18 19 22 25 29 32 37 37 38
find the median (25)
with 11,13,18,19,22 find the middle for that (18) Q1
with 29,32,37,37,38 find the middle for that (37)Q3
Q3-Q1
37-18=19
Since the painting is hung in center of a rectangular wall ,the distance between them on either side will be the same.so we can divide the length of the painting and wall by 2.we will get 2.4/2=1.2 feet and 20/2=10 feet .10-1.2=8.8 feet gives the distance between the right edge of the painting and right edge of the wall
Answer:
a)0.08 , b)0.4 , C) i)0.84 , ii)0.56
Step-by-step explanation:
Given data
P(A) = professor arrives on time
P(A) = 0.8
P(B) = Student aarive on time
P(B) = 0.6
According to the question A & B are Independent
P(A∩B) = P(A) . P(B)
Therefore
& 
is also independent
= 1-0.8 = 0.2
= 1-0.6 = 0.4
part a)
Probability of both student and the professor are late
P(A'∩B') = P(A') . P(B') (only for independent cases)
= 0.2 x 0.4
= 0.08
Part b)
The probability that the student is late given that the professor is on time
= 
= 
= 0.4
Part c)
Assume the events are not independent
Given Data
P
= 0.4
=
= 0.4
= 0.4 x P
= 0.4 x 0.4 = 0.16
= 0.16
i)
The probability that at least one of them is on time
= 1-
= 1 - 0.16 = 0.84
ii)The probability that they are both on time
P
= 1 - 
= 1 - ![[P({A}')+P({B}') - P({A}'\cap {B}')]](https://tex.z-dn.net/?f=%5BP%28%7BA%7D%27%29%2BP%28%7BB%7D%27%29%20-%20P%28%7BA%7D%27%5Ccap%20%7BB%7D%27%29%5D)
= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56
