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3 years ago

Solve for m. m + 4 3 = 2 what is m HELP MEEEEE!!!!!!!!!!!

Mathematics

2 answers:

Anna71 [15]3 years ago

7 0

hi there user! Looks like your looking for help, so Mizuki came here to help you!

the answer is:

m is 2/3

The whole work I did:

m + 4 ÷ 3 = 2

m + 4/3 = 2

m + 4/3 - 4/3 = 2 - 4/3

m = 6/3 - 4/3

m = 2/3

Anyways hope this helped! qwq

Radda [10]3 years ago

7 0

M is -41. If you add 43 to -41, your result will be 2. A number line would help you, too.

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Between what two limits , expressed in degrees , are all acute angles found? All obtuse angles?

Tomtit [17]

Answer:

Acute angles are less than 90 degrees, obtuse angles are more than 90 degrees, and right angles are exactly 90 degrees.Step-by-step explanation:

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3 years ago

WHAT IS EQUIVALENT TO THE INEQUALITY y/2 -6 <8 ? PLEASE HURRY ITS DUE 10:50

Oksanka [162]

Y/2 - 6 < 8
y/2 < 14
y < 7

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3 years ago

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Find the value of unknown angle x,y,z,a,b,c with reasons and full process

Oduvanchick [21]

Answer:

Step-by-step explanation:

x = 70 degree (being vertically opposite angles)

y + 70 degree =180 degree (being linear pair)

y = 180 - 70

y = 110 degree

In triangle,

x + 60 + misssing angle = 180 degree (sum of interior angles of a triangle)

70 + 60 + missing angle =180

130 + missing angle = 180

missing angle = 180 - 130

missing angle = 50 degree

c = missing angle (being vertically opposite angles )

c = 50 degree

x + missing angle = a (sum of two interior opposite angles is equal to the exterior angle formed)

70 + 50 = a

120 degree = a

a = b (being vertically opposite angle

120 =b

therefore b is 120 degree

Hence , a = 120 degree , b = 120 degree , c = 50 degree , x = 70 degree , y = 110 degree

7 0

3 years ago

Unit 8 right triangles and trigonometry homework 3 similar right triangles and geometric mean

Ugo [173]

The right triangles that have an altitude which forms two right triangles

are similar to the two right triangles formed.

Responses:

1. ΔLJK ~ ΔKJM

ΔLJK ~ ΔLKM

ΔKJM ~ ΔLKM

2. ΔYWZ ~ ΔZWX

ΔYWZ ~ ΔYZW

ΔZWX ~ ΔYZW

3. x = 4.8

4. x ≈ 14.48

5. x ≈ 11.37

6. G.M. = 12·√3

7. G.M. = 6·√5

<h3>What condition guarantees the similarity of the right triangles?</h3>

1. ∠LMK = 90° given

∠JMK + ∠LMK = 180° linear pair angles

∠JMK = 180° - 90° = 90°

∠JKL ≅ ∠JMK All 90° angles are congruent

∠LJK ≅ ∠LJK reflexive property

ΔLJK is similar to ΔKJM by Angle–Angle, AA, similarity postulate

∠JLK ≅ ∠JLK by reflexive property

ΔLJK is similar to ΔLKM by AA similarity

By the property of equality for triangles that have equal interior angles, we have;

ΔKJM ~ ΔLKM

2. ∠YWZ ≅ ∠YWZ by reflexive property

∠WXZ ≅ ∠YZW all 90° angle are congruent

ΔYWZ is similar to ΔZWX, by AA similarity postulate

∠XYZ ≅ ∠WYZ by reflexive property

∠YXZ ≅ ∠YZW all 90° are congruent

ΔYWZ is similar to ΔYZW by AA similarity postulate

Therefore;

ΔZWX ~ ΔYZW

3. The ratio of corresponding sides in similar triangles are equal

From the similar triangles, we have;

$\dfrac{8}{10} = \mathbf{ \dfrac{x}{6}}$

8 × 6 = 10 × x

48 = 10·x

$x = \dfrac{48}{10} = \underline{4.8}$

3. From the similar triangles, we have;

$\mathbf{\dfrac{20}{29}} = \dfrac{x}{21}$

20 × 21 = x × 29

420 = 29·x

$x = \dfrac{420}{29 } \approx \underline{14.48}$

4. From the similar triangles, we have;

$\mathbf{\dfrac{20}{52}} = \dfrac{x}{48}$

20 × 48 = 52 × x

$x = \dfrac{20 \times 48}{52} = \dfrac{240}{13} \approx \underline{18.46}$

5. From the similar triangles, we have;

$\mathbf{\dfrac{13.2}{26}} = \dfrac{x}{22.4}$

13.2 × 22.4 = 26 × x

$x = \dfrac{13.2 \times 22.4}{26} \approx \underline{ 11.37}$

6. The geometric mean, G.M. is given by the formula;

$G.M. = \mathbf{\sqrt[n]{x_1 \times x_2 \times x_3 ... x_n}}$

The geometric mean of 16 and 27 is therefore;

$G.M. = \sqrt[2]{16 \times 27} = \sqrt[2]{432} = \sqrt[2]{144 \times 3} = \mathbf{12 \cdot \sqrt{3}}$

The geometric mean of 16 and 27 is 12·√3

7. The geometric mean of 5 and 36 is found as follows;

$G.M. = \sqrt[2]{5 \times 36} = \sqrt[2]{180} = \sqrt[2]{36 \times 5} = \mathbf{ 6 \cdot \sqrt{5}}$

The geometric mean of 5 and 36 is 6·√5

Learn more about the AA similarity postulate and geometric mean here:

brainly.com/question/12002948

brainly.com/question/12457640

7 0

3 years ago

How do i solve this? (1/3x-11)^(1/2)=5

photoshop1234 [79]

$(\frac{1}{3} x-11)^{ \frac{1}{2} }=5\\ ((\frac{1}{3} x-11)^{ \frac{1}{2} })^{2}=(5)^{2}\\ \frac{1}{3} x-11=25\\ \frac{1}{3} x=36\\x=108$

4 0

3 years ago

Read 2 more answers