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Paha777 [63]
3 years ago
6

Can you help me with this please

Mathematics
1 answer:
nlexa [21]3 years ago
4 0

Answer:

Hypothesis: If I am at least 16 years and 6 months old

Conclusion: Then I am able to get a provisional license

I hope this helps!

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Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

You're minimizing d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2} subject to the constraint f(x,y,z)=x+y+z=1. Note that d(x,y,z) and d(x,y,z)^2 attain their extrema at the same values of x,y,z, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
7 0
3 years ago
Bethany wears jeans every 2 days. She wears running shoes every 3 days. If she wears jeans with running shoes on May 1, what are
Vladimir [108]
May 7, May 13, May 20.
This is because the pattern is (Black is not wearing):
Jeans: ⚫️⚫️⚫️
Shoes: ⚫️⚫️⚫️⚫️
8 0
3 years ago
Look closely at the model.
Maslowich

Answer:

Perimeter: 2(x+3) + 2(x+2)

Step-by-step explanation:

6 0
3 years ago
Mr. See weights his grades. Tests are worth 60%, quizzes are worth 25% and homework is 15%. Joey's test average is an 82, his qu
goldenfox [79]

Answer:

83.15

Step-by-step explanation:

Joey's current grade can be determined by weighting his scores with the weights given and adding the results

Tests = 0.6 x 82 = 49.2

Quizzes = 0.25 x 77 = 19.25

homework = 0.15 x 98 = 14.7

49.2 + 19.25 + 14.7 = 83.15

4 0
3 years ago
You want to give your friend a soccer ball for a gift. The soccer ball has a
Ede4ka [16]

Answer:

volume of cube share box = 67.92 inch²

Step-by-step explanation:

given data

soccer ball volume = 85.3π cubic inches

solution

we know that ball will fit inside the box when box length will be equal to diameter of ball

and here soccer ball volume will be express as

soccer ball volume = \frac{4}{3}\times \pi \times r^3      .................1

85.3π  =  \frac{4}{3}\times \pi \times r^3    

solve it we get

r³ = 69.9765

r = 4.12 inch

so diameter = 2 × 4.12 = 8.24 inch

diameter = length of box side

volume of cube share box = a²

volume of cube share box = 8.24²

volume of cube share box = 67.92 inch²

6 0
3 years ago
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