Answer:
4 2/15
Step-by-step explanation:
okay so let's first change 1/3 and 1/5 into the same fraction,
the common denominator, is 15
3 times 5, to get to fifteen,
so
5/15 and 3/15
minus eachother
2/15
6-2 is 4
4 2/15
Answer:
Solution given:
For 1st
x²=71
For x=±
and
For 2nd
x³=71
For x=±![\sqrt[3]{71}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B71%7D)
So answer is:
In first row
<u>Solution to x²=71</u>
In second row
<u>Solution to </u><u>x³</u><u>=71</u>
In third row
<u>neither</u>
In forth row
<u>Solution to x³=71</u>
80 because tens place is two over from the right
A=6
2*6=12
12-8=4
B=6
3*6=18
18-8=10
Answer is b hope this helps