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34kurt
2 years ago
15

A soccer team has two games in two days against different teams. Let A represent the event "the soccer team wins the first game"

and B represent the event "the soccer team wins the second game." Use the above scenario when answering the following three questions.
1. Describe the meaning of P(B | A).
2. Do you think A and B are independent events? Explain your reasoning.
3. If the events are independent, how are P(B (A) and P(B) related? How come?​
Mathematics
1 answer:
Maksim231197 [3]2 years ago
5 0
The answer for this is B because
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Please help!! asap!!! ( 10 points)
MAXImum [283]

Answer:

......................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................

Step-by-step explanation:

5 0
3 years ago
Help me please owo due today​
Allushta [10]

Answer:

the area of the mat = total area added minus the original area of the water color painting.

length of the mat is:

L = 21 in + 3 in + 3 in because 3 in  is added to each side

L = 27 inwidth of the mat is:w = 11 in + 3 in + 3 inw = 17in

Area mat = (27 in x 17 in) - ( 21 in x 27 in)

area mat = 108 sq in is the area of the mat

4 0
3 years ago
Read 2 more answers
Are the marks one receives in a course related to the amount of time spent studying the subject? To analyze this mysterious poss
sertanlavr [38]

Answer:

a) 98.522

b) 0.881

c) The correlation coefficient and co-variance shows that there is positive association between marks and study time. The correlation coefficient suggest that there is strong positive association between marks and study time.

Step-by-step explanation:

a.

As the mentioned in the given instruction the co-variance is first computed in excel by using only add/Sum, subtract, multiply, divide functions.

Marks y Time spent x y-ybar x-xbar (y-ybar)(x-xbar)

77                    40 5.1         1.3 6.63

63                     42 -8.9            3.3 -29.37

79                     37 7.1            -1.7 -12.07

86                     47 14.1            8.3 117.03

51                    25 -20.9  -13.7 286.33

78                     44 6.1            5.3 32.33

83                      41 11.1            2.3 25.53

90                     48 18.1            9.3 168.33

65                     35 -6.9           -3.7 25.53

47                    28 -24.9 -10.7 266.43

Covariance=\frac{sum[(y-ybar)(x-xbar)]}{n-1}

Co-variance=886.7/(10-1)

Co-variance=886.7/9

Co-variance=98.5222

The co-variance computed using excel function COVARIANCE.S(B1:B11,A1:A11) where B1:B11 contains Time x column and A1:A11 contains Marks y column. The resulted co-variance is 98.52222.

b)

The correlation coefficient is computed as

Correlation coefficient=r=\frac{sum[(y-ybar)(x-xbar)]}{\sqrt{sum[(x-xbar)]^2sum[(y-ybar)]^2} }

(y-ybar)^2 (x-xbar)^2

26.01        1.69

79.21       10.89

50.41             2.89

198.81       68.89

436.81       187.69

37.21       28.09

123.21        5.29

327.61        86.49

47.61         13.69

620.01         114.49

sum(y-ybar)^2=1946.9

sum(x-xbar)^2=520.1

Correlation coefficient=r=\frac{886.7}{\sqrt{520.1(1946.9)} }

Correlation coefficient=r=\frac{886.7}{\sqrt{1012582.69} }

Correlation coefficient=r=\frac{886.7}{1006.2717 }

Correlation coefficient=r=0.881

The correlation coefficient computed using excel function CORREL(A1:A11,B1:B11) where B1:B11 contains Time x column and A1:A11 contains Marks y column. The resulted correlation coefficient is 0.881.

c)

The correlation coefficient and co-variance shows that there is positive association between marks and study time. The correlation coefficient suggest that there is strong positive association between marks and study time. It means that as the study time increases the marks of student also increases and if the study time decreases the marks of student also decreases.

The excel file is attached on which all the related work is done.

Download xlsx
7 0
3 years ago
Blake said 4/5+1/3 =5/8 does his answer make sense explain. please help
Tatiana [17]
Hey there!

The answer is no because whenever you add or subtract fractions, you find the common denominator(the bottom of the fraction)

Corret way:
The common denominator is 15 (5*3)
Multiply numerator(top) and the denominator by 3 
4/5*3*3= 12/15
Multiply numerator and the denominator by 5
1/3*5/5= 5/15
So the equation is now
12/15+5/15= 17/15 or 1 2/15

Hope this helps! :)
7 0
3 years ago
If DF=78, DE=5x-9, and EF=2x+10, find DE.
Kazeer [188]

Given that E is a point between Point D and F, the numerical value of segment DE is 46.

<h3>What is the numerical value of DE?</h3>

Given the data in the question;

  • E is a point between point D and F.
  • Segment DF = 78
  • Segment DE = 5x - 9
  • Segment EF = 2x + 10
  • Numerical value of DE = ?

Since E is a point between point D and F.

Segment DF = Segment DE + Segment EF

78 = 5x - 9 + 2x + 10

78 = 7x + 1

7x = 78 - 1

7x = 77

x = 77/7

x = 11

Hence,

Segment DE = 5x - 9

Segment DE = 5(11) - 9

Segment DE = 55 - 9

Segment DE = 46

Given that E is a point between Point D and F, the numerical value of segment DE is 46.

Learn more about equations here: brainly.com/question/14686792

#SPJ1

3 0
1 year ago
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