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3 years ago

Someone please help me answer this!!

Mathematics

2 answers:

Aleks04 [339]3 years ago

5 0

Answer:

8.5 m

Step-by-step explanation:

If you draw the segment from one corner to the opposite corner, you'll have the hypotenuse of a triangle with two legs of 6 m. We can find the length of the hypotenuse using the Pythagorean Theorem.

a^2 + b^2 = c^2

6^2 + 6^2 = c^2

36 + 36 = c^2

c^2 = 72

c = sqrt(72)

c = 6sqrt(2) = 8.5

Answer: 8.5 m

earnstyle [38]3 years ago

4 0

Answer:

c = 8.4m is the answer.

Step-by-step explanation:

a = 6m

b = 6m

c = ?

According to the Pythagorean theorem,

a² + b² = c²

6² + 6² = c²

36 + 36 = c²

c² = 72

c = 8.4m

∴ The mouse runs 8.4 m from the opposite corners of the room.

You might be interested in

A shop sells a particular of video recorder. Assuming that the weekly demand for the video recorder is a Poisson variable with t

julia-pushkina [17]

Answer:

a) 0.5768 = 57.68% probability that the shop sells at least 3 in a week.

b) 0.988 = 98.8% probability that the shop sells at most 7 in a week.

c) 0.0104 = 1.04% probability that the shop sells more than 20 in a month.

Step-by-step explanation:

For questions a and b, the Poisson distribution is used, while for question c, the normal approximation is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

In which

x is the number of successes

e = 2.71828 is the Euler number

$\lambda$ is the mean in the given interval.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The Poisson distribution can be approximated to the normal with $\mu = \lambda, \sigma = \sqrt{\lambda}$ , if $\lambda>10$ .

Poisson variable with the mean 3

This means that $\lambda= 3$ .

(a) At least 3 in a week.

This is $P(X \geq 3)$ . So

$P(X \geq 3) = 1 - P(X < 3)$

In which:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

Then

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0498 + 0.1494 + 0.2240 = 0.4232$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 1 - 0.4232 = 0.5768$

0.5768 = 57.68% probability that the shop sells at least 3 in a week.

(b) At most 7 in a week.

This is:

$P(X \leq 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

In which

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

$P(X = 4) = \frac{e^{-3}*3^{4}}{(4)!} = 0.1680$

$P(X = 5) = \frac{e^{-3}*3^{5}}{(5)!} = 0.1008$

$P(X = 6) = \frac{e^{-3}*3^{6}}{(6)!} = 0.0504$

$P(X = 7) = \frac{e^{-3}*3^{7}}{(7)!} = 0.0216$

Then

$P(X \leq 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.0498 + 0.1494 + 0.2240 + 0.2240 + 0.1680 + 0.1008 + 0.0504 + 0.0216 = 0.988$

0.988 = 98.8% probability that the shop sells at most 7 in a week.

(c) More than 20 in a month (4 weeks).

4 weeks, so:

$\mu = \lambda = 4(3) = 12$

$\sigma = \sqrt{\lambda} = \sqrt{12}$

The probability, using continuity correction, is P(X > 20 + 0.5) = P(X > 20.5), which is 1 subtracted by the p-value of Z when X = 20.5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20 - 12}{\sqrt{12}}$

$Z = 2.31$

$Z = 2.31$ has a p-value of 0.9896.

1 - 0.9896 = 0.0104

0.0104 = 1.04% probability that the shop sells more than 20 in a month.

5 0

3 years ago

HEEELLLPPP PLEEAAASEEE

Pavel [41]

Answer:

B. y = 2.5

Step-by-step explanation:

Diane's average speed= 25/y km/h.

Ed's speed= (25/y) - 6 km/h.

Ed walks 25-3 = 22 km.

Consider Ed's journey:

Speed = distance / time so:

(25/y) - 6 = 22 / (y + 3) ( 3 hours longer = y + 3)

(25 /y - 6)(y + 3) = 22

25 + 75/y - 6y - 18 = 22

6y - 75/y = 25 - 18 - 22

6y - 75/y + 15 = 0

6y^2 + 15y - 75 = 0

2y^2 + 5y - 25 = 0

(2y - 5 )(y + 5) = 0

y = 2.5, -5.

y = 2.5 ( as it must be positive.

4 0

3 years ago

What is the value of i 20+1?<br> 1<br> –1<br> –i<br> i

3241004551 [841]

Answer:

Step-by-step explanation:

i^2 = -1

i^4 = 1

i^20 repeats the cycle 5 times, making i^20 = 1

4 0

3 years ago

Read 2 more answers

you burn 10 calories each minute you jog.What integer represents the change in your calories after you jog for 20 mins

Hoochie [10]

The total calories burnt in 20 minutes are 200

Step-by-step explanation:

We have to do simple multiplication to find the number of calories burnt.

Given

Number of calories burnt in one minute = c = 10

Time = t = 20 min

So the total number of calories burnt in 20 minutes will be:

$C_t = c * t\\= 10 * 20\\=200\ calories$

Hence,

The total calories burnt in 20 minutes are 200

Keywords: Integers, unit

Learn more about integers at:

#LearnwithBrainly

7 0

3 years ago

100 POINTS FOR ANSWERS AND BRAINIEST WITH THANKS AND RATING

lisabon 2012 [21]

Commutative property of addition:

a + b = b + a

Associative property of addition:

a + (b + c) = (a + b) + c

Opposite of a sum:

- a - b = - (a + b)

If we look at the options, A and D follow associative property.

B follows commutative property.

C follows opposite of a sum property.

3 0

4 years ago