Answer:
v= 6km/h - 1km/h^2 * t
Step-by-step explanation:
From the information, it seems the runner is slowing down because the speed at 1st hour is 5km/h but at 3rd hour becomes 3km/h.
If v= velocity, v0= initial speed, t= time, and the a=acceleration then the function would be:
v= v0 + a * t
To find the acceleration you need to do this equation:
acceleration= velocity1- velocity3 / t3-t1
a = (3km/h-5km/h)/ (3 hour- 1 hour)
a = (-2km/h)/2hour= -1 km/hour^2
After that, you need to find the initial speed. Try to put the 1st-hour variable into the full equation. It would look like this
v= v0 + a * t
5km/h= v0 + (-1 km/hour^2 * 1 hour)
v0= 5km/h + 1km/h
v0= 6km/h
Then the full function would be:
v= 6km/h - 1km/h^2 * t
The graph would look like a backslash(\) from 5 gradually go down to 1.
6
5 O
4 O
3 O
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1 2 3 4 5
Answer:
Step-by-step explanation:
=
=
Answer:
4.31
Step-by-step explanation:
Find the cube root of both sides of the equation.
= 
The cube root will cancel out the cubed in the variable.
v =
Find the cube root of 80. I rounded to the nearest hundredth.
v = 4.31
Solution:
The Preimage function is , F(x)=|x|
Consider a point (a,b) on the function, F(x)=|x|. it means
b=|a|-----(1) satisfies the function.
Now the function F(x)=|x| is vertically stretched by 5 units.It means
x=a , y= b+5
x=a, b=y-5
So, putting the value of a and b in equation (1).
y-5=|x|
y= |x| + 5 is vertical stretch of y= |x| by 5 units.
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