tysm luv this #FleePointsForFlee thing!!!!! :))))
Answer:
(-∞, -5/2) ∪ (1, ∞)
Step-by-step explanation:
"Increasing" means the graph goes up to the right. It is increasing from the left up to the local maximum--the peak at left.
It is increasing again from the local minimum on the right to the right side of the graph.
The two sections where the graph is increasing are ...
(-∞, -5/2) ∪ (1, ∞)
__
The graph is <em>decreasing</em> between the maximum on the left and the minimum on the right.
Answer:
a. v(t)= -6.78
+ 16.33 b. 16.33 m/s
Step-by-step explanation:
The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=
=
. We now multiply both sides of the equation by the integrating factor.
μv' + μkv = μg ⇒
v' + k
v = g
⇒ [v
]' = g
. Integrating, we have
∫ [v
]' = ∫g
v
= 
+ c
v(t)=
+ c
.
From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have
9.55 = 9.8 × 15/9 + c
= 16.33 + c
c = 9.55 -16.33 = -6.78.
So, v(t)= 16.33 - 6.78
. m/s = - 6.78
+ 16.33 m/s
b. Velocity of object at time t = 0.5
At t = 0.5, v = - 6.78
+ 16.33 m/s = 16.328 m/s ≅ 16.33 m/s
Answer:
48% is 12/25 as a fraction. So C
Answer:

Step-by-step explanation:
We are given that a student needs to make a square cardboard piece.
Perimeter of cardboard should be equal to atleast 92 inches
We have to find that which shows reasonable domain for f(s)
Let s be the side of square cardboard
We know that perimeter of square =f(s=)
Then, perimeter of cardboard=

Dividing by 4 on both sides

Hence, the domain of function
Therefore, option d is true.
Answer:d: 