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rodikova [14]
3 years ago
9

Please help me if you can. Please also write how you got the answer thank you.

Mathematics
1 answer:
babunello [35]3 years ago
4 0

Answer:

Question 9: Variables: (smallest) s, q, r (largest)

Question 10: 5 whole numbers (7, 8, 9, 10, and 11)

Step-by-step explanation:

For question nine, there are two given statements... s=q-2 and q<r. Say we plug in 10000 (a really big #) in for q, then we would get s=9998 and r>10000. This way, we can see that s would be the smallest, then q, and r is the largest. <em>(q<r can be written as r>q)</em>

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For question 10, it states \frac{1}{4}. This can be split into \frac{3}{x} and \frac{3}{x} . When x is 12 in the first equation then \frac{3}{12} = \frac{1}{4} and when x is 6 in the second equation \frac{3}{6} =0.5 (0.5 is also  \frac{1}{2}). Therefore, x must be a whole number less than 12 and greater than 6, and it cannot be either 12 or 6. Whole numbers between 6 and 12 are 7, 8, 9, 10, and 11  or  5 whole numbers.

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Answer: 8359

Step-by-step explanation:

The formula for sample size needed for interval estimate of population proportion :-

n=p(1-p)(\frac{z_{\alpha/2}}{E})^2

Given : The significance level : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}}=z_{0.025}=\pm1.96

Previous estimate of proportion : p=0.32

Margin of error : E=0.01

Now, the required sample size will be :-

n=0.32(1-0.32)(\frac{1.96}{0.01})^2=8359.3216\approx8359

Hence, the required sample size = 8359

5 0
3 years ago
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dezoksy [38]

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3 0
3 years ago
If AC=12, BC=3, find CE<br> 1) 3 square root of 3<br> 2) 6<br> 3) 18
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Answer:

2) 6

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7 0
3 years ago
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Given sin theta = 1/3 and 0 theta pi/2 find tan 2 theta
Kazeer [188]

Answer:

\tan2\theta=\pm\dfrac{4\sqrt{2}}{7}

Step-by-step explanation:

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Multiply both sides by 2

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2theta lie in I and II quadrant.

\tan2\theta is positive in I and negative in II quadrant.

\sin\theta=\dfrac{1}{3}

\cos\theta=\dfrac{2\sqrt{2}}{3}

\sin2\theta=2\sin\theta\cos\theta

\sin2\theta=2\cdot \dfrac{1}{3}\cdot \dfrac{2\sqrt{2}}{3}=\dfrac{4\sqrt{2}}{9}

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\tan2\theta=\pm\dfrac{4\sqrt{2}}{7}

Hence, The value of \tan2\theta=\pm\dfrac{4\sqrt{2}}{7}

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3 years ago
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