Answer:
The answer is "26.208 km"
Explanation:
Given value:
Formula:
Answer:
149.34 Giga meter is the distance d from the center of the sun at which a particle experiences equal attractions from the earth and the sun.
Explanation:
Mass of earth = m =
Mass of Sun = M = 333,000 m
Distance between Earth and Sun = r = 149.6 gm = 1.496\times 10^{11} m[/tex]
1 giga meter =
Let the mass of the particle be m' which x distance from Sun.
Distance of the particle from Earth = (r-x)
Force between Sun and particle:
Force between Sun and particle:
Force on particle is equal:
F = F'
= ±577.06
Case 1:
x =
Acceptable as the particle will lie in between the straight line joining Earth and Sun.
Case 2:
x =
Not acceptable as the particle will lie beyond on line extending straight from the Earth and Sun.
We know that AD is the shortest way but ABCD is connected in series
Equivalent Resistance =R1+R2+R3
=(10+10+10)ohm
=30ohm
Since BC and AD is connected in parallel
1/Req=1/R1 + 1/R2
=1/30 + 1/10
=3+1/30
=4/30
So, Req=30/4 ohm
Now,Current drawn from the battery
=> I = V/R
=> I = 30/4 ohm/3v
=> I = 30/4*3
So, I = 10/4 A
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D. Volume will increase
Volume and temperature are directly proportional for a gas.
Answer:
38 m/s
43 m/s
Explanation:
x = 18t + 5.0t²
The instantaneous velocity is the first derivative:
v = 18 + 10.t
At t = 2.0:
v = 18 + 10.(2.0)
v = 38 m/s
The average velocity is the change in position over change in time.
v = Δx / Δt
v = [ (18t₂ + 5.0t₂²) − (18t₁ + 5.0t₁²) ] / (t₂ − t₁)
Between t = 2.0 and t = 3.0:
v = [ (18(3.0) + 5.0(3.0)²) − (18(2.0) + 5.0(2.0)²) ] / (3.0 − 2.0)
v = [ (54 + 45) − (36 + 20.) ] / 1.0
v = 99 − 56
v = 43 m/s