Answer:
Explanation:
Potential energy on the surface of the earth
= - GMm/ R
Potential at height h
= - GMm/ (R+h)
Potential difference
= GMm/ R - GMm/ (R+h)
= GMm ( 1/R - 1/ R+h )
= GMmh / R (R +h)
This will be the energy needed to launch an object from the surface of Earth to a height h above the surface.
Extra energy is needed to get the same object into orbit at height h
= Kinetic energy of the orbiting object at height h
= 1/2 x potential energy at height h
= 1/2 x GMm / ( R + h)
Answer:
No distance is the length between two routes
Explanation:
Distance is the length of the route between two points. ... Direction is just as important as distance in describing motion. A vector is a quantity that has both size and direction. It can be used to represent the distance and direction of motion.
Answer:
Explanation:
κ = 1/v x dv/dp
= 1/ρ x (+δρ/ δp )_T
δρ = 1 , ρ = 100
44.18 x 10⁻⁶ = ( 1/100) x( 1 / δp)
δp = 10⁻² / (44.18 x 10⁻⁶ )
= .0226 x 10⁴
= 226 bar
Two colliding objects will exert equal forces upon each other. If the objects have different masses, then these equal forces will produce different accelerations.
